[enhancement] partitionMuti

[cabbage89]

function partitionMuti(array,every){

var arr=[];
_.each(array,function(n,index){
var rem = Math.floor(index / every);
if (index% every == 0)
arr[rem] = [];
arr[rem].push(n);
});
return arr;
}

[cabbage89]

_.partitionMuti([1,2,3,4,5,6,7,8,9],3) == [[1,2,3],[4,5,6],[7,8,9]]

[jdalton]

It's _.chunk.

[megawac]

Duplicate of #1891 #1919