551. Student Attendance Record IEasy

/*
551. Student Attendance Record I

You are given a string representing an attendance record for a student. The record only contains the following three characters:

    'A' : Absent.
    'L' : Late.
    'P' : Present.

A student could be rewarded if his attendance record doesn't contain more than one 'A' (absent) or more than two continuous 'L' (late).

You need to return whether the student could be rewarded according to his attendance record.

Example 1:

Input: "PPALLP"
Output: True

Example 2:

Input: "PPALLL"
Output: False
*/
//思路：出现两个以上的A或者三个连续的L，就输出false。否则输出true
//19ms   1.7%
bool checkRecord(char* s) {
    int i;
    int num[1]={0};
    for( i = 0 ; i < strlen(s) ; i++)
        if(s[i]=='A')
            num[0]++;
        else if(s[i]=='L')
                if( s[i+1] && s[i+2] && s[i+1] == 'L' && s[i+2] == 'L')
                    return false;
   if(num[0]>1)
        return false;
    
    return true;
}