DictSegment匹配函数代码

[GoogleCodeExporter]

DictSegment.java中第89-92行：
for(DictSegment seg : segmentArray){
    if(seg != null && seg.nodeChar.equals(keyChar)){
        //找到匹配的段
        ds = seg;
    }
}
其中ds=seg;找到匹配之后似乎应该break跳出for循环

Original issue reported on code.google.com by scomouse@163.com on 28 Apr 2010 at 3:41

[GoogleCodeExporter]

非常感谢您的意见，我们将在下个版本修订。

Original comment by linliang...@gmail.com on 14 May 2010 at 4:06

[GoogleCodeExporter]

问题已经修订，详见源码更新记录

Original comment by linliang...@gmail.com on 14 May 2010 at 4:24

• Changed state: Done