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DictSegment.java中第89-92行: for(DictSegment seg : segmentArray){ if(seg != null && seg.nodeChar.equals(keyChar)){ //找到匹配的段 ds = seg; } } 其中ds=seg;找到匹配之后似乎应该break跳出for循环
Original issue reported on code.google.com by scomouse@163.com on 28 Apr 2010 at 3:41
scomouse@163.com
The text was updated successfully, but these errors were encountered:
非常感谢您的意见,我们将在下个版本修订。
Original comment by linliang...@gmail.com on 14 May 2010 at 4:06
linliang...@gmail.com
Sorry, something went wrong.
问题已经修订,详见源码更新记录
Original comment by linliang...@gmail.com on 14 May 2010 at 4:24
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Original issue reported on code.google.com by
scomouse@163.com
on 28 Apr 2010 at 3:41The text was updated successfully, but these errors were encountered: