Licence clarification

[kloczek]

In PKG-INFO it is:

License: UNKNOWN

However LICENSE content looks very simillar to MIT licence.
Similar but not the same :)
https://opensource.org/licenses/MIT/

[jmcantrell]

I'm not sure what you're referring to. The license is defined in setup.py as BSD, and github recognizes it as BSD zero clause. Closing this for now.

[kloczek]

Indeed it is in setup.py:

        'License :: OSI Approved :: BSD License',

Issue is that there are at least 3 BSD licenses.
BSD-2-Clause (https://opensource.org/licenses/BSD-2-Clause/)
BSD-3-Clause (https://opensource.org/licenses/BSD-3-Clause/)
BSD-4-Clause (https://spdx.org/licenses/BSD-4-Clause.html)
And that License tag is noit propagated into generated PKG-INFO file.

[kloczek]

And what is lin LICENSE file looks more like MIT (https://opensource.org/licenses/MIT/)

[jmcantrell]

It looks like there's not a recommended solution yet for the trove classifier imprecision:

pypa/trove-classifiers#17
https://discuss.python.org/t/pep-639-improving-license-clarity-with-better-package-metadata/2154

Regarding the license file, it's exactly this:
https://opensource.org/licenses/0BSD