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分析
vi
a
解答:
因为:
S = v * t
v = (vi + vf) / 2
vf = vi + a * t
所以:
S = (vi + vi + a * t) / 2 * t
化简可得:
S = vi*t + a*t^2/2
答案:
S = 19.6*t + 4.9*t*t
demo http://jsfiddle.net/8w3579nf/5/
The text was updated successfully, but these errors were encountered:
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题目:以19.6m/s的速度向垂直向上抛射小球,问小球关于时间t轨迹方程?
分析
vi
(初速度):19.6m/s (抛出物体的速度)a
(加速度):-9.8m/s (不考虑空气阻力,小球的下落速度 = 重力加速度 = 9.8m/s,方向与抛物方向相反所以规定为负数)解答:
因为:
S = v * t
(距离 = 平均速度*时间)v = (vi + vf) / 2
(平均速度 = (初速度+末速度)/2)vf = vi + a * t
(末速度 = 初速度 + 加速度 * t)所以:
S = (vi + vi + a * t) / 2 * t
化简可得:
S = vi*t + a*t^2/2
答案:
S = 19.6*t + 4.9*t*t
demo http://jsfiddle.net/8w3579nf/5/
The text was updated successfully, but these errors were encountered: