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CandyCrush.java
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CandyCrush.java
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package Leetcode;
/**
* @author kalpak
*
* This question is about implementing a basic elimination algorithm for Candy Crush.
*
* Given a 2D integer array board representing the grid of candy, different positive integers board[i][j] represent different types of candies.
* A value of board[i][j] = 0 represents that the cell at position (i, j) is empty.
* The given board represents the state of the game following the player's move.
*
* Now, you need to restore the board to a stable state by crushing candies according to the following rules:
* - If three or more candies of the same type are adjacent vertically or horizontally, "crush" them all at the same time - these positions become empty.
* - After crushing all candies simultaneously, if an empty space on the board has candies on top of itself,
* then these candies will drop until they hit a candy or bottom at the same time. (No new candies will drop outside the top boundary.)
* - After the above steps, there may exist more candies that can be crushed. If so, you need to repeat the above steps.
* - If there does not exist more candies that can be crushed (ie. the board is stable), then return the current board.
*
* You need to perform the above rules until the board becomes stable, then return the current board.
*
* Example:
*
* Input:
* board = [[110,5,112,113,114],
* [210,211,5,213,214],
* [310,311,3,313,314],
* [410,411,412,5,414],
* [5,1,512,3,3],
* [610,4,1,613,614],
* [710,1,2,713,714],
* [810,1,2,1,1],
* [1,1,2,2,2],
* [4,1,4,4,1014]]
*
* Output:
* [[0,0,0,0,0],
* [0,0,0,0,0],
* [0,0,0,0,0],
* [110,0,0,0,114],
* [210,0,0,0,214],
* [310,0,0,113,314],
* [410,0,0,213,414],
* [610,211,112,313,614],
* [710,311,412,613,714],
* [810,411,512,713,1014]]
*
* Explanation:
* Note:
*
* The length of board will be in the range [3, 50].
* The length of board[i] will be in the range [3, 50].
* Each board[i][j] will initially start as an integer in the range [1, 2000].
*/
public class CandyCrush {
public static int[][] candyCrush(int[][] board) {
int row = board.length;
int col = board[0].length;
boolean found = true;
while(found) {
found = false;
for(int i = 0; i < row; i++) {
for(int j = 0; j < col; j++) {
int cellValue = Math.abs(board[i][j]);
if(cellValue == 0)
continue;
// For each cell,
// if there are at least three candies of the same type rightward or downward,
// set them all to its negative value to mark them.
if(j < col - 2 && Math.abs(board[i][j + 1]) == cellValue && Math.abs(board[i][j + 2]) == cellValue) {
found = true;
int index = j;
while (index < col && Math.abs(board[i][index]) == cellValue)
board[i][index++] = -cellValue;
}
if(i < row - 2 && Math.abs(board[i + 1][j]) == cellValue && Math.abs(board[i + 2][j]) == cellValue) {
found = true;
int index = i;
while (index < row && Math.abs(board[index][j]) == cellValue)
board[index++][j] = -cellValue;
}
}
}
// After each traversal,
// we need to remove all those negative values by setting them to 0,
// then let the rest drop down to their correct position.
if(found) {
// A easy way is to iterate through each column -
// For each column, move positive values to the bottom then set the rest to 0.
for(int j = 0; j < col; j++) {
int runningRowIndex = row - 1;
for(int i = row - 1; i >= 0; i--) {
if(board[i][j] > 0) {
board[runningRowIndex][j] = board[i][j];
runningRowIndex--;
}
}
for(int k = runningRowIndex; k >= 0; k--)
board[k][j] = 0;
}
}
}
return board;
}
public static void printBoard(int[][] board) {
for(int i = 0; i < board.length; i++) {
for(int j = 0; j < board[0].length; j++)
System.out.print(board[i][j] + " ");
System.out.println();
}
}
public static void main(String[] args) {
int[][] board = new int[][]{{110,5,112,113,114},{210,211,5,213,214},{310,311,3,313,314},
{410,411,412,5,414},{5,1,512,3,3},{610,4,1,613,614},{710,1,2,713,714},
{810,1,2,1,1},{1,1,2,2,2},{4,1,4,4,1014}};
System.out.println("Board before move.");
printBoard(board);
candyCrush(board);
System.out.println("Board after a move.");
printBoard(board);
}
}