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LC1646-Get-Maximum-in-Generated-Array.py
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LC1646-Get-Maximum-in-Generated-Array.py
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"""
You are given an integer n. An array nums of length n + 1 is generated in the following way:
nums[0] = 0
nums[1] = 1
nums[2 * i] = nums[i] when 2 <= 2 * i <= n
nums[2 * i + 1] = nums[i] + nums[i + 1] when 2 <= 2 * i + 1 <= n
Return the maximum integer in the array nums.
Example 1:
Input: n = 7
Output: 3
Explanation: According to the given rules:
nums[0] = 0
nums[1] = 1
nums[(1 * 2) = 2] = nums[1] = 1
nums[(1 * 2) + 1 = 3] = nums[1] + nums[2] = 1 + 1 = 2
nums[(2 * 2) = 4] = nums[2] = 1
nums[(2 * 2) + 1 = 5] = nums[2] + nums[3] = 1 + 2 = 3
nums[(3 * 2) = 6] = nums[3] = 2
nums[(3 * 2) + 1 = 7] = nums[3] + nums[4] = 2 + 1 = 3
Hence, nums = [0,1,1,2,1,3,2,3], and the maximum is 3.
Example 2:
Input: n = 2
Output: 1
Explanation: According to the given rules, the maximum between nums[0],
nums[1], and nums[2] is 1.
Example 3:
Input: n = 3
Output: 2
Explanation: According to the given rules, the maximum between nums[0],
nums[1], nums[2], and nums[3] is 2.
Constraints:
0 <= n <= 100
"""
from run_tests import run_tests
class Solution:
def getMaximumGenerated(self, n: int) -> int:
"""
Generate the array as described above and dynamically find the max
:param n: the length of the target array
:return: max value
"""
memo = {0: 0, 1: 1}
if n < 2:
return memo[n]
max_val = 0
for i in range(2, n + 1):
if not i % 2:
memo[i] = memo[i // 2]
else:
memo[i] = memo[i // 2] + memo[(i + 1) // 2]
max_val = max(max_val, memo[i])
return max_val
if __name__ == "__main__":
"""
f(2) = f(1)
f(3) = f(2) + f(1) = 2f(1)
f(4) = f(1)
f(5) = f(2) + f(3) = 3f(1)
f(6) = f(3) = 2f(1)
f(7) = f(3) + f(4) = 3f(1)
f(8) = f(1)
f(9) = f(4) + f(5) = 4f(1)
f(10) = 3f(1)
f(11) = 5f(1)
f(12) = 2f(1)
f(13)= 5f(1)
f(14) = f(7) = 3f(1)
f(15) = 4f(1)
"""
correct_answers = [
[0, 0],
[1, 1],
[2, 1],
[3, 2],
[4, 2],
[7, 3],
[15, 5],
[100, 21]
]
print('Starting tests for getMaximumGenerated')
run_tests(Solution().getMaximumGenerated, correct_answers)