ignore script_name if part of URI

[kzap]

Why not ignore $_SERVER['SCRIPT_NAME'] if its part of the URI being dispatched?

so that /index.php/ and / are the same
incase your frontend controller is frontend.php so /frontend.php/ and / are the same also

Line 87:

        // if SCRIPT_NAME is part of the REQUEST_URI, remove it from $uri since we ignore it
        if ($_SERVER['SCRIPT_NAME'] == substr($_SERVER['REQUEST_URI'], 0, strlen($_SERVER['SCRIPT_NAME']))) {
            $uri = substr($_SERVER['REQUEST_URI'], strlen($_SERVER['SCRIPT_NAME']));
        }

[chriso]

Because that's just one potential way of routing.

dispatch() takes a single optional argument, $uri, which defaults to $_SERVER['REQUEST_URI'].

In your case, simply replace your dispatch() call with dispatch(substr($_SERVER['REQUEST_URI'], strlen($_SERVER['SCRIPT_NAME'])));

[kzap]

k this is what i did:

// if SCRIPT_NAME is part of the REQUEST_URI, remove it from $uri since we ignore it
if ($_SERVER['SCRIPT_NAME'] == substr($_SERVER['REQUEST_URI'], 0, strlen($_SERVER['SCRIPT_NAME']))) {
        $dispatchUri = substr($_SERVER['REQUEST_URI'], strlen($_SERVER['SCRIPT_NAME']));
} else {
        $dispatchUri = $_SERVER['REQUEST_URI'];
}
dispatch($dispatchUri);