Implement an iterator to flatten a 2d vector.
Example:
Input: 2d vector =
[
[1,2],
[3],
[4,5,6]
]
Output: [1,2,3,4,5,6]
Explanation: By calling next repeatedly until hasNext returns false,
the order of elements returned by next should be: [1,2,3,4,5,6].
太简单了……
class Vector2D(object):
def __init__(self, vec2d):
"""
Initialize your data structure here.
:type vec2d: List[List[int]]
"""
self.arr = []
for arr in vec2d:
self.arr += arr
def next(self):
"""
:rtype: int
"""
return self.arr.pop(0)
def hasNext(self):
"""
:rtype: bool
"""
return len(self.arr) > 0
# Your Vector2D object will be instantiated and called as such:
# i, v = Vector2D(vec2d), []
# while i.hasNext(): v.append(i.next())