RSS 2.0 Parser

Requirements

Golang 1.13+, 1.14+

Getting It

You can get go-rss by using

$ go get -u github.com/kostya-ten/go-rss

Parse rss file

  import "github.com/kostya-ten/go-rss"

  func main() {
    feed, err := rss.ParseFile(filename)
    if err != nil {
      panic(err)
    }

    title := feed.Channel.Title
    fmt.Println(title)
  }

Parse rss url

  import "github.com/kostya-ten/go-rss"

  func main() {
    feed, err := rss.ParseURL("http://static.userland.com/gems/backend/rssTwoExample2.xml", &http.Client{})
    if err != nil {
      panic(err)
    }

    title := feed.Channel.Title
    fmt.Println(title)
  }

Bulk parse rss url

  import "github.com/kostya-ten/go-rss"

  func main() {
    urls := []string{
      "https://lenta.ru/rss",
      "https://www.interfax.ru/rss.asp",
      "https://ria.ru/export/rss2/index.xml",
      "http://static.feed.rbc.ru/rbc/logical/footer/news.rss",
      "http://tass.ru/rss/v2.xml",
      "https://www.vesti.ru/vesti.rss",
    }

    resultRss := rss.ParseBulk(urls, &http.Client{}, &BulkOptions{maxgoroutine: 10, buffer_chan: 10})
    for _, v := range resultRss {
      fmt.Println(v.Channel.Title)
    }
  }