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lesson9_3_MaxDoubleSliceSum.rb
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lesson9_3_MaxDoubleSliceSum.rb
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# A non-empty array A consisting of N integers is given.
# A triplet (X, Y, Z), such that 0 ≤ X < Y < Z < N, is called a double slice.
# The sum of double slice (X, Y, Z) is the total of A[X + 1] + A[X + 2] + ... + A[Y − 1] + A[Y + 1] + A[Y + 2] + ... + A[Z − 1].
# For example, array A such that:
# A[0] = 3
# A[1] = 2
# A[2] = 6
# A[3] = -1
# A[4] = 4
# A[5] = 5
# A[6] = -1
# A[7] = 2
# contains the following example double slices:
# double slice (0, 3, 6), sum is 2 + 6 + 4 + 5 = 17,
# double slice (0, 3, 7), sum is 2 + 6 + 4 + 5 − 1 = 16,
# double slice (3, 4, 5), sum is 0.
# The goal is to find the maximal sum of any double slice.
# Write a function:
# def solution(a)
# that, given a non-empty array A consisting of N integers, returns the maximal sum of any double slice.
# For example, given:
# A[0] = 3
# A[1] = 2
# A[2] = 6
# A[3] = -1
# A[4] = 4
# A[5] = 5
# A[6] = -1
# A[7] = 2
# the function should return 17, because no double slice of array A has a sum of greater than 17.
# Write an efficient algorithm for the following assumptions:
# N is an integer within the range [3..100,000];
# each element of array A is an integer within the range [−10,000..10,000].
def solution(a)
max_starting =(a.length - 2).downto(0).each.inject([[],0]) do |(acc,max), i|
[acc, acc[i]= [0, a[i] + max].max ]
end.first
max_ending =1.upto(a.length - 3).each.inject([[],0]) do |(acc,max), i|
[acc, acc[i]= [0, a[i] + max].max ]
end.first
max_ending.each_with_index.inject(0) do |acc, (el,i)|
[acc, el.to_i + max_starting[i+2].to_i].max
end
end