设计一个函数，奇数次执行的时候打印 1，偶数次执行的时候打印 2

[lgwebdream]

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[lgwebdream]

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[523451928]

function test() {
  test.count = test.count ? test.count+1 : 1
  if (test.count % 2 === 0) {
    console.log(2)
  } else {
    console.log(1)
  }
}
test()

[GolderBrother]

function countFn() {
    let count = 0;
    return function (...args) {
        count++;
        if (count & 1 === 1) return console.log(1);
        console.log(2);
    }
}
const testFn = countFn();
testFn(); // 1
testFn(); // 2
testFn(); // 1
testFn(); // 2
testFn(); // 1
testFn(); // 2

[dty999]

function* Print() {
  while (true) {
    yield console.log('1');
    yield console.log('2');
  }
}
let p = Print()
function myprint() {
  p.next()
}
myprint()
myprint()
myprint()

}

[xingdongyu1994]

let a = (function () {
	let num = 0
	return function () {
		num++
		return num % 2 === 0 ? 2 : 1
	}
})()

[gaohan1994]

最直接的思路是使用闭包

const oddEvenConsole = () => {
  let count = 0;
  return function () {
    const isEven = count % 2 === 0;
    console.log(isEven ? 2 : 1);
    count++;
  };
};