Not found ULR (stop char missing)

[oxozle]

If there is no valid left stop char and there is no space in string valid url not found.
Example string:
スマホの方はこちらをクリック➡https://line.me/R/ti/p/%40pnd3781y

[lipoja]

Thank you for your time and reporting this issue. I really appreciate it.
I am thinking about it and I am not sure how to solve it. Do you have any suggestion?

This library is not able to cover all possibilities. I am trying to make compromise in a lot of thinks which are set as default. However I am always thinking about usability and therefore urlextract class has methods such as set_stop_chars_left(). I know that every text (page) is different and user should know what text is parsing and what to expect. This library should provide you all necessary functions/methods to tune it to fit users needs.

[lipoja]

@oxozle Is it OK for you to use internal methods to set your own stop characters based on the page you are parsing?
I still did not came up with any general solution.

[lipoja]

@oxozle I do not have any reply for 2 months. I am closing this issue since I think method set_stop_chars_left() can be used to solve this issue.

Feel free to reopen it any time.