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Problem238_productOfArrayExceptSelf.java
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Problem238_productOfArrayExceptSelf.java
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package com.longluo.top100;
import java.util.Arrays;
/**
* 238. 除自身以外数组的乘积
* <p>
* 给你一个整数数组 nums,返回 数组 answer ,其中 answer[i] 等于 nums 中除 nums[i] 之外其余各元素的乘积 。
* 题目数据 保证 数组 nums之中任意元素的全部前缀元素和后缀的乘积都在 32 位 整数范围内。
* <p>
* 请不要使用除法,且在 O(n) 时间复杂度内完成此题。
* <p>
* 示例 1:
* 输入: nums = [1,2,3,4]
* 输出: [24,12,8,6]
* <p>
* 示例 2:
* 输入: nums = [-1,1,0,-3,3]
* 输出: [0,0,9,0,0]
* <p>
* 提示:
* 2 <= nums.length <= 10^5
* -30 <= nums[i] <= 30
* 保证 数组 nums之中任意元素的全部前缀元素和后缀的乘积都在 32 位 整数范围内
* <p>
* 进阶:你可以在 O(1) 的额外空间复杂度内完成这个题目吗?( 出于对空间复杂度分析的目的,输出数组不被视为额外空间。)
* <p>
* https://leetcode.com/problems/product-of-array-except-self/
*/
public class Problem238_productOfArrayExceptSelf {
// BF time: O(n^2) space: O(1)
// TimeOut
public static int[] productExceptSelf_bf(int[] nums) {
int len = nums.length;
int[] ans = new int[len];
for (int i = 0; i < len; i++) {
int product = 1;
for (int j = 0; j < i; j++) {
product *= nums[j];
}
for (int j = i + 1; j < len; j++) {
product *= nums[j];
}
ans[i] = product;
}
return ans;
}
// Prefix time: O(3 * n) = O(n) space: O(n)
public static int[] productExceptSelf_prefix(int[] nums) {
int len = nums.length;
int[] left = new int[len + 1];
int[] right = new int[len + 1];
left[0] = 1;
// Left[i] = nums[0] * nums[1] ... nums[i]
for (int i = 0; i < len; i++) {
left[i + 1] = nums[i] * left[i];
}
right[len] = 1;
// right[i] = nums[len - 1] * nums[len - 2] ... nums[i]
for (int i = len - 1; i >= 0; i--) {
right[i] = nums[i] * right[i + 1];
}
int[] ans = new int[len];
for (int i = 0; i < len; i++) {
ans[i] = left[i] * right[i + 1];
}
return ans;
}
// Prefix Opt time: O(n) space: O(n)
public static int[] productExceptSelf_prefix_opt(int[] nums) {
int len = nums.length;
int[] ans = new int[len];
int[] left = new int[len];
int[] right = new int[len];
left[0] = 1;
// Left[i] = nums[0] * nums[1] ... nums[i - 1]
for (int i = 1; i < len; i++) {
left[i] = nums[i - 1] * left[i - 1];
}
right[len - 1] = 1;
// right[i] = nums[len - 1] * nums[len - 2] ... nums[i + 1]
for (int i = len - 2; i >= 0; i--) {
right[i] = nums[i + 1] * right[i + 1];
}
for (int i = 0; i < len; i++) {
ans[i] = left[i] * right[i];
}
return ans;
}
// Prefix time: O(2n) space: O(1)
public static int[] productExceptSelf(int[] nums) {
int len = nums.length;
int[] ans = new int[len];
ans[0] = 1;
// ans[i] = nums[0] * nums[1] ... nums[i - 1]
for (int i = 1; i < len; i++) {
ans[i] = nums[i - 1] * ans[i - 1];
}
int right = 1;
for (int i = len - 1; i >= 0; i--) {
ans[i] = ans[i] * right;
right *= nums[i];
}
return ans;
}
// Prefix Opt time: O(n) space: O(1)
public static int[] productExceptSelf_Opt(int[] nums) {
int len = nums.length;
int[] ans = new int[len];
Arrays.fill(ans, 1);
int left = 1;
int right = 1;
for (int i = 0; i < len; i++) {
ans[i] = ans[i] * left;
ans[len - i - 1] = ans[len - i - 1] * right;
left = left * nums[i];
right = right * nums[len - i - 1];
}
return ans;
}
public static void main(String[] args) {
System.out.println("[24,12,8,6] ?= " + Arrays.toString(productExceptSelf_bf(new int[]{1, 2, 3, 4})));
System.out.println("[0,0,9,0,0] ?= " + Arrays.toString(productExceptSelf_bf(new int[]{-1, 1, 0, -3, 3})));
System.out.println("[12,16,24,48,24] ?= " + Arrays.toString(productExceptSelf_prefix(new int[]{4, 3, 2, 1, 2})));
System.out.println("[24,12,8,6] ?= " + Arrays.toString(productExceptSelf_prefix(new int[]{1, 2, 3, 4})));
System.out.println("[0,0,9,0,0] ?= " + Arrays.toString(productExceptSelf_prefix(new int[]{-1, 1, 0, -3, 3})));
System.out.println("[0,0,9,0,0] ?= " + Arrays.toString(productExceptSelf_prefix_opt(new int[]{-1, 1, 0, -3, 3})));
System.out.println("[24,12,8,6] ?= " + Arrays.toString(productExceptSelf(new int[]{1, 2, 3, 4})));
System.out.println("[24,12,8,6] ?= " + Arrays.toString(productExceptSelf_Opt(new int[]{1, 2, 3, 4})));
}
}