New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Jump to bottom

在 sequelize 中使用 sql 条件判断 #150

Open

lovelmh13 opened this issue Jul 26, 2021 · 0 comments

Owner

lovelmh13 commented Jul 26, 2021

const { Sequelize } = require('sequelize')
  
Sequelize.literal('CASE status WHEN 1 THEN 0 ELSE status END'), // 如果 status 是 1 就改成0，其他状态不变

注意：如果不写 ElSE status，那么除了匹配到的 1 变成0，其他的都会变成 NULL

【Mysql-3】条件判断函数-CASE WHEN、IF、IFNULL详解

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment