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191002 Compressing a string.py
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191002 Compressing a string.py
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https://leetcode.com/problems/decode-string/
# This is an input example 3[abc]4[ab]c
# This is the result calculaion = 3 * "abc" + 4 * "ab" + "c"
import re
seq = "3[abc]4[ab]c"
seq2 = seq.replace("[", "*")
seq3 = seq2.replace("]", "+")
index = 1
for i in seq4:
try:
x = int(i)
if x in range(10000):
print(x)
else:
continue
if seq4[index] not in range(10000):
print(int(i) * seq4[index])
seq = "3[abc]4[ab]c"
seq2 = seq.replace("[", " ")
seq3 = seq2.replace("]", " ")
seq4 = seq3.split()
result = []
numbers = re.findall("[0-9]", seq)
index = 0
for i in seq4:
print(i)
if i in numbers:
print(i)
print(numbers)
new_seq = int(i) * seq4[1]
print(new_seq)
result.append(new_seq)
seq4 = seq4[1:]
print(seq4)
numbers.remove(i)
print(numbers)
index+=1
print(index)
else:
# if seq4[index+1] not in numbers:
# seq4.insert(1, 1)
seq4 = seq4[1:]
index+=1
del seq4[0:2]
seq4.insert(0, new_seq)
for i in numbers:
if i in seq4:
new_seq = int(i) * seq4[index+1]
print(new_seq)
print(i)
re.findall("[0-9]", seq)
re.search("[0-9]", seq)
re.finditer("[0-9]", seq)
re.match("3", seq)
re.split("[\[\]]", seq)