Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Handle empty tibble for tidytable::unnest. #530

Closed
roboton opened this issue Jul 11, 2022 · 0 comments · Fixed by #531
Closed

Handle empty tibble for tidytable::unnest. #530

roboton opened this issue Jul 11, 2022 · 0 comments · Fixed by #531
Labels
bug Something isn't working

Comments

@roboton
Copy link
Contributor

roboton commented Jul 11, 2022

Handling of empty tibble inconsistent with tidyr::unnest

> tidytable::unnest.(tibble::tibble(foo = list()), foo)
Error in .l[[1]] : subscript out of bounds
> tidyr::unnest(tibble::tibble(foo = list()), foo)
# A tibble: 0 × 1
# … with 1 variable: foo <???>
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
bug Something isn't working
Projects
None yet
Development

Successfully merging a pull request may close this issue.

2 participants