Should be possible to spread Parameters onto its function

[Svish]

TypeScript Version: 3.7.5

Search Terms:
function parameters spread

Expected behavior:
Expected the playground example to compile without errors

Actual behavior:
The code works great, but Typescript throws the following error:

Type 'Parameters' must have a 'Symbol.iterator' method that returns an iterator. (2488)

Code

export function call<F extends (...args: any) => any>(
  fn: F,
  ...parameters: Parameters<F>
): ReturnType<F> {
  return fn(...parameters);
}

Playground Link: Provided

[patrickshipe]

As a workaround, ...args: [...Parameters<T>] works.

[haggen]

Use (...args: any[]) => any and it'll work: Playground

On a tangent, IMO, this looks a bit classier:

function call<F extends (...args: any[]) => any, P extends any[] = Parameters<F>, R = ReturnType<F>>(
  fn: F,
  ...parameters: P
): R {
  return fn(...parameters);
}

[haggen]

I'm still uncertain of how to achieve that in strict mode though.

[MartinJohns]

As mentioned by @AlCalzone in #41728, this seems to work when replacing any with any[].