Skip to content
New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

[ERROR] [action.handler] error while fire action PjsipHandleEventsAction with args () and kwargs {'timeout': 50} for event_name OnTimeTick #33

Closed
motom001 opened this issue Jan 27, 2015 · 1 comment

Comments

@motom001
Copy link
Owner

Fehlermeldung:

C2015-01-27 22:42:24,050 [ERROR]       [action.handler] error while fire action PjsipHandleEventsAction with args () and kwargs {'timeout': 50} for event_name OnTimeTick
Traceback (most recent call last):
  File "/home/pi/doorpi/doorpi/action/handler.py", line 140, in fire_event_synchron
    action.run(silent)
  File "/home/pi/doorpi/doorpi/action/base.py", line 48, in run
    return self.__callback(**self.__kwargs)
  File "/home/pi/doorpi/doorpi/action/SingleActions/pjsip_handle_events.py", line 15, in pjsip_handle_events
    doorpi.DoorPi().sipphone.lib.handle_events(timeout)
  File "/usr/local/lib/python2.7/dist-packages/pjsua.py", line 2258, in handle_events
    return _pjsua.handle_events(timeout)
KeyboardInterrupt
@motom001
Copy link
Owner Author

Kommt vor wenn man DoorPi beenden will aber mit dem KeyboardInterrupt den handler von pjsua erwischt.
Ist nicht schlimm, der wird kurz darauf wieder aufgerufen - nur die Fehlermeldung ist unschön...

Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Projects
None yet
Development

No branches or pull requests

1 participant