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Add new BDD example: TAOCP exercise 43. #10

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msk-ono opened this issue Sep 30, 2023 · 0 comments

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msk-ono commented Sep 30, 2023

: $f(x_1, \dots, x_{2n}) = [x_1 + \dots + x_n = x_{n+1} + \dots + x_{2n}]$
: $f(x_1, \dots, x_{2n}) = [x_1 + x_3 + \dots + x_{2n-1} = x_2 + x_4 + \dots + x_{2n}]$

msk-ono changed the title ~~Add new example: TAOCP 43.~~ Add new BDD example: TAOCP exercise 43.

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