/
registry.go
111 lines (91 loc) · 2.2 KB
/
registry.go
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package check
import (
"errors"
"fmt"
"sync"
)
type checkRegistry struct {
mu sync.RWMutex
checks map[string]Check
groups map[string][]Check
}
var (
registry *checkRegistry
initOnce sync.Once
)
// 注册检查项,每个检查使用init()进行注册
func Register(check Check) error {
initOnce.Do(func() {
registry = &checkRegistry{
checks: make(map[string]Check),
groups: make(map[string][]Check),
}
})
registry.mu.Lock()
defer registry.mu.Unlock()
name := check.Name()
if name == "" {
return errors.New("checks must have non-empty names")
}
if _, ok := registry.checks[name]; ok {
return fmt.Errorf("check named %q already exists", name)
}
registry.checks[name] = check
for _, group := range check.Groups() {
registry.groups[group] = append(registry.groups[group], check)
}
return nil
}
// 列出所有注册的检查
func List() []Check {
registry.mu.RLock()
defer registry.mu.RUnlock()
ret := make([]Check, 0, len(registry.checks))
for _, check := range registry.checks {
ret = append(ret, check)
}
return ret
}
// 列出所有注册的组
func ListGroups() []string {
registry.mu.RLock()
defer registry.mu.RUnlock()
ret := make([]string, 0, len(registry.groups))
for group := range registry.groups {
ret = append(ret, group)
}
return ret
}
// GetGroup 返回特定组中的检查
func GetGroup(name string) []Check {
registry.mu.RLock()
defer registry.mu.RUnlock()
ret := make([]Check, 0, len(registry.groups[name]))
for _, check := range registry.groups[name] {
ret = append(ret, check)
}
return ret
}
// GetGroups 返回属于返回多个组的检查
func GetGroups(groups []string) ([]Check, error) {
registry.mu.RLock()
defer registry.mu.RUnlock()
var ret []Check
for _, group := range groups {
if checks, ok := registry.groups[group]; ok {
ret = append(ret, checks...)
} else {
return nil, fmt.Errorf("group %s not found", group)
}
}
return ret, nil
}
// Get从registry中检索指定的检查名如果为空抛出错误
func Get(name string) (Check, error) {
registry.mu.RLock()
defer registry.mu.RUnlock()
if registry.checks[name] != nil {
return registry.checks[name], nil
}
return nil, fmt.Errorf("check not found: %s", name)
}