New issue
Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.
By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.
Already on GitHub? Sign in to your account
postal.parser.parse_address() returns a list instead of a dict #27
Comments
Easiest route from my experience is: {k: v for (v, k) in parse_address('330 11th Ave Apt 1')} |
Yes, that's what I did. What I first did not see was that the order of the output tuple was always the same. The issue is solved, thank you! |
Hi @antimirov, yes, the dictionary comprehension should do the trick. As a quick background on why it's formatted this way, the underlying sequence model takes an array of tokens like this: ['1010', 'easy', 'st', 'ottawa', 'k1a', '0b1'] and predicts an equal-length array of labels, one per token, like this: ['house_number', 'road', 'road', 'city', 'postcode', 'postcode'] For convenience, we roll those up into phrases wherever there's a contiguous sequence of the same label. However, a dictionary would make an implicit assumption that there's only one of each address component. Most of the time, and for most components, this is true. The output roughly corresponds to fields that one might store in a database or search index. It's usually a parser mistake when there are duplicate components, but in, say, India, the UK, Ireland, etc. it's possible to see something like "{venue/company name} {road} {house name}" in which case there might be two different legitimate components tagged Note: the address parser client from the C library prints something that looks like JSON, but it's not necessarily valid, as there can be duplicate keys. It's just easier to visualize the output as pseudo-JSON on the command line. |
Would it be possible to return the tuples in the opposite order? If the keys come first you can do On a related topic, it might be nice to think of this as a multi-dict. This is pretty common in the web world, e.g. for headers. |
Just began using libpostal and decided to try its python binding.
Whats I immediately noticed is that comparing to the command-line 'src/address_parser' the corresponding python function return a list. Compare:
src/address_parser:
Result:
{
"house_number": "1010",
"road": "easy st",
"city": "ottawa",
"postcode": "k1a 0b1"
}
python postal:
I could not find a way to output the data in a more organized, JSON way. What's the reason it's done like that? Is it always guaranteed to have a value as a first element, and a key as a second?
Please advise.
The text was updated successfully, but these errors were encountered: