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Kaem will pass -- when substituting $@ #21
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well yes. if you use bash and do the exact same thing it will include the -- in the $@ expansion. However if you have a bootstrap specific reason for this deviation in behavior from bash it certainly would be considered and possibly adopted. |
I don't need kaem to deviate but: echo "$@" with kaem:
with bash:
I'm using kaem to wrap mes and mescc and not being able to pass arguments through the wrapper is troublesome. |
I could add an option like --done that would enable that behavior: so kaem -f something.sh --done asd to produce your desired results. |
That won't work in a shebang as far I'm aware sadly |
with a kame script
the output will be
-- arguments...
if called with./script -- arguments...
, I'd expect the output to be justecho arguments...
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