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Evaluation of the expression should be consistent between python engine and numexpr engine. I assume the python engine behavior would be the preferred behavior.
Expected Output
df.eval('a + a', engine='numexpr')
0 NaN
1 NaN
Name: a, dtype: object
I assume the python engine behavior would be the preferred behavior.
this function is designed around speeding up large operations, not providing full compatibility for numexpr, thus arbitrary operations are just not supported.
if you want to provide support for additional things great.
Code Sample, a copy-pastable example if possible
Problem description
Evaluation of the expression should be consistent between python engine and numexpr engine. I assume the python engine behavior would be the preferred behavior.
Expected Output
Output of
pd.show_versions()
INSTALLED VERSIONS
commit: None
python: 3.6.2.final.0
python-bits: 64
OS: Linux
OS-release: 3.13.0-143-generic
machine: x86_64
processor: x86_64
byteorder: little
LC_ALL: None
LANG: en_US.UTF-8
LOCALE: en_US.UTF-8
pandas: 0.23.0
pytest: None
pip: 9.0.1
setuptools: 36.4.0
Cython: None
numpy: 1.13.1
scipy: None
pyarrow: None
xarray: None
IPython: None
sphinx: None
patsy: None
dateutil: 2.6.1
pytz: 2017.2
blosc: None
bottleneck: None
tables: None
numexpr: 2.6.5
feather: None
matplotlib: None
openpyxl: None
xlrd: None
xlwt: None
xlsxwriter: None
lxml: None
bs4: None
html5lib: None
sqlalchemy: None
pymysql: None
psycopg2: None
jinja2: None
s3fs: None
fastparquet: None
pandas_gbq: None
pandas_datareader: None
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