load_dict.py

#A parser for the CC-Cedict. Convert the Chinese-English dictionary into a list of python dictionaries with "traditional","simplified", "pinyin", and "english" keys.

#Make sure that the cedict_ts.u8 file is in the same folder as this file, and that the name matches the file name on line 13.

#Before starting, open the CEDICT text file and delete the copyright information at the top. Otherwise the program will try to parse it and you will get an error message.

#Characters that are commonly used as surnames have two entries in CC-CEDICT. This program will remove the surname entry if there is another entry for the character. If you want to include the surnames, simply delete lines 59 and 60.

#This code was written by Franki Allegra in February 2020.

#open CEDICT file
from os.path import dirname, join, abspath

curr_dir = dirname(abspath(__file__))
file_path = join(curr_dir, 'cedict_ts.u8')
with open(file_path, encoding="utf-8") as file:
    text = file.read()
    lines = text.split('\n')
    dict_lines = list(lines)

#define functions

    def parse_line(line):
        parsed = {}
        if line == '':
            dict_lines.remove(line)
            return 0
        line = line.rstrip('/')
        line = line.split('/')
        if len(line) <= 1:
            return 0
        # english = ";".join(line[1:])
        english = line[1:]
        char_and_pinyin = line[0].split('[')
        characters = char_and_pinyin[0]
        characters = characters.split()
        traditional = characters[0]
        simplified = characters[1]
        # if simplified == '贡献':
        #     print(english)
        pinyin = char_and_pinyin[1]
        pinyin = pinyin.rstrip()
        pinyin = pinyin.rstrip("]")
        parsed['traditional'] = traditional
        parsed['simplified'] = simplified
        parsed['pinyin'] = pinyin
        parsed['english'] = english
        list_of_dicts.append(parsed)

    def remove_surnames():
        for x in range(len(list_of_dicts)-1, -1, -1):
            if "surname " in list_of_dicts[x]['english']:
                if list_of_dicts[x]['traditional'] == list_of_dicts[x+1]['traditional']:
                    list_of_dicts.pop(x)
            
    def load_dict():

        #make each line into a dictionary
        print("Parsing dictionary . . .")
        for line in dict_lines:
                parse_line(line)
        
        #remove entries for surnames from the data (optional):

        print("Removing Surnames . . .")
        remove_surnames()

        # Turn list into dict of dicts

        new_dict = {}
        for entry in list_of_dicts:
            new_dict[entry['simplified']] = entry

        return new_dict


        #If you want to save to a database as JSON objects, create a class Word in the Models file of your Django project:

        # print("Saving to database (this may take a few minutes) . . .")
        # for one_dict in list_of_dicts:
        #     new_word = Word(traditional = one_dict["traditional"], simplified = one_dict["simplified"], english = one_dict["english"], pinyin = one_dict["pinyin"], hsk = one_dict["hsk"])
        #     new_word.save()
        print('Done!')

list_of_dicts = []
# parsed_dict = load_dict()
# print(type(parsed_dict["贡献"]['english']))