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roadfix_dp2_trees.cc
98 lines (82 loc) · 2.42 KB
/
roadfix_dp2_trees.cc
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#include <cstdio>
#include <algorithm>
using namespace std;
const size_t MAXN = 10000;
const long INF = 0x3f3f3f3f;
const long MAXVAL = 1000000000;
const long MAXNODES = 60*MAXN;
long N, M, qX, qY, ans[MAXN+1], l[MAXNODES], r[MAXNODES], minim[MAXNODES], currNode;
struct segment{
long X, Y, C;
} seg[MAXN+1];
bool comp(segment A, segment B) {
return A.Y < B.Y;
}
long Left(long v) {
if (!l[v]) {
l[v] = ++currNode;
minim[currNode] = INF;
}
return l[v];
}
long Right(long v) {
if (!r[v]) {
r[v] = ++currNode;
minim[currNode] = INF;
}
return r[v];
}
long Minimum(long from, long v=1, long x=0, long y=MAXVAL) {
if(x==from) return minim[v];
long mid=(x+y)/2;
if (mid < from) return Minimum(from, Right(v), mid+1, y);
return min( Minimum(from, Left(v), x, mid), minim[Right(v)] );
}
void Add(long pos, long val, long v=1, long x=0, long y=MAXVAL) {
if (x==y) {
minim[v] = min(minim[v],val);
return;
}
long mid=(x+y)/2;
if(pos<=mid) Add(pos, val, Left(v), x, mid);
else Add(pos, val, Right(v), mid+1, y);
minim[v] = min(minim[Left(v)],minim[Right(v)]);
}
int main() {
FILE *fi = fopen("roadfix.in", "r");
fscanf(fi, "%ld %ld", &N, &M);
for (long i = 1; i <= N; ++i) {
fscanf(fi, "%ld %ld %ld", &seg[i].X, &seg[i].Y, &seg[i].C);
seg[i].Y += seg[i].X; //convert length to right-end-point
}
sort(seg+1, seg+N+1, comp);
FILE *fo = fopen("roadfix.out", "w");
long sol;
for(long q = 1; q <= M; ++q) {
fscanf(fi, "%ld %ld", &qX, &qY);
qY += qX; //convert length to right-end-point
sol = INF;
currNode = 1;
for(long i=1; i<=N; ++i) {
//Find best j that finishes after (or exactly at) i's start
long best = (seg[i].X <= qX ) ? 0 : INF;
best = min(best, Minimum(seg[i].X));
if (best==INF) { //if no previous segment finishes before i's start
if (seg[i].Y <= qX) ans[i] = 0; // [qX,seg[i].Y] is trivially satisfied
else if (seg[i].X <= qX) ans[i] = seg[i].C; //i is enough to satisfy it
else ans[i] = INF; //i is not enough and no-one else can help
}
else ans[i] = seg[i].C + best; //recursive relation
Add(seg[i].Y, ans[i]);
if (seg[i].Y >= qY) sol = min(sol, ans[i]);
}
if (sol < INF) fprintf(fo, "%ld\n", sol);
else fprintf(fo, "-1\n");
for(long i=1; i<=currNode; ++i) {
l[i] = r[i] = 0;
minim[i] = INF;
}
}
fclose(fi), fclose(fo);
return 0;
}