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Why p1 = &arr[0]; and p2 = &arr[0].? These pointers can point to different elements of the array (for example p1 = &arr[1];, p2 = &arr[3];).
p1 = &arr[0];
p2 = &arr[0].
p1 = &arr[1];
p2 = &arr[3];
The text was updated successfully, but these errors were encountered:
Why p1 = &arr[0]; and p2 = &arr[0].?
Because they point to the same array, rather than the elements of same array. But the statements make no sense. Sorry for the misleading.
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Why
p1 = &arr[0];
andp2 = &arr[0].
?These pointers can point to different elements of the array (for example
p1 = &arr[1];
,p2 = &arr[3];
).The text was updated successfully, but these errors were encountered: