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join.sql
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join.sql
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--
-- JOIN
-- Test JOIN clauses
--
CREATE TABLE J1_TBL (
i integer,
j integer,
t text
);
CREATE TABLE J2_TBL (
i integer,
k integer
);
INSERT INTO J1_TBL VALUES (1, 4, 'one');
INSERT INTO J1_TBL VALUES (2, 3, 'two');
INSERT INTO J1_TBL VALUES (3, 2, 'three');
INSERT INTO J1_TBL VALUES (4, 1, 'four');
INSERT INTO J1_TBL VALUES (5, 0, 'five');
INSERT INTO J1_TBL VALUES (6, 6, 'six');
INSERT INTO J1_TBL VALUES (7, 7, 'seven');
INSERT INTO J1_TBL VALUES (8, 8, 'eight');
INSERT INTO J1_TBL VALUES (0, NULL, 'zero');
INSERT INTO J1_TBL VALUES (NULL, NULL, 'null');
INSERT INTO J1_TBL VALUES (NULL, 0, 'zero');
INSERT INTO J2_TBL VALUES (1, -1);
INSERT INTO J2_TBL VALUES (2, 2);
INSERT INTO J2_TBL VALUES (3, -3);
INSERT INTO J2_TBL VALUES (2, 4);
INSERT INTO J2_TBL VALUES (5, -5);
INSERT INTO J2_TBL VALUES (5, -5);
INSERT INTO J2_TBL VALUES (0, NULL);
INSERT INTO J2_TBL VALUES (NULL, NULL);
INSERT INTO J2_TBL VALUES (NULL, 0);
-- useful in some tests below
create temp table onerow();
insert into onerow default values;
analyze onerow;
--
-- CORRELATION NAMES
-- Make sure that table/column aliases are supported
-- before diving into more complex join syntax.
--
SELECT *
FROM J1_TBL AS tx;
SELECT *
FROM J1_TBL tx;
SELECT *
FROM J1_TBL AS t1 (a, b, c);
SELECT *
FROM J1_TBL t1 (a, b, c);
SELECT *
FROM J1_TBL t1 (a, b, c), J2_TBL t2 (d, e);
SELECT t1.a, t2.e
FROM J1_TBL t1 (a, b, c), J2_TBL t2 (d, e)
WHERE t1.a = t2.d;
--
-- CROSS JOIN
-- Qualifications are not allowed on cross joins,
-- which degenerate into a standard unqualified inner join.
--
SELECT *
FROM J1_TBL CROSS JOIN J2_TBL;
-- ambiguous column
SELECT i, k, t
FROM J1_TBL CROSS JOIN J2_TBL;
-- resolve previous ambiguity by specifying the table name
SELECT t1.i, k, t
FROM J1_TBL t1 CROSS JOIN J2_TBL t2;
SELECT ii, tt, kk
FROM (J1_TBL CROSS JOIN J2_TBL)
AS tx (ii, jj, tt, ii2, kk);
SELECT tx.ii, tx.jj, tx.kk
FROM (J1_TBL t1 (a, b, c) CROSS JOIN J2_TBL t2 (d, e))
AS tx (ii, jj, tt, ii2, kk);
SELECT *
FROM J1_TBL CROSS JOIN J2_TBL a CROSS JOIN J2_TBL b;
--
--
-- Inner joins (equi-joins)
--
--
--
-- Inner joins (equi-joins) with USING clause
-- The USING syntax changes the shape of the resulting table
-- by including a column in the USING clause only once in the result.
--
-- Inner equi-join on specified column
SELECT *
FROM J1_TBL INNER JOIN J2_TBL USING (i);
-- Same as above, slightly different syntax
SELECT *
FROM J1_TBL JOIN J2_TBL USING (i);
SELECT *
FROM J1_TBL t1 (a, b, c) JOIN J2_TBL t2 (a, d) USING (a)
ORDER BY a, d;
SELECT *
FROM J1_TBL t1 (a, b, c) JOIN J2_TBL t2 (a, b) USING (b)
ORDER BY b, t1.a;
-- test join using aliases
SELECT * FROM J1_TBL JOIN J2_TBL USING (i) WHERE J1_TBL.t = 'one'; -- ok
SELECT * FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE J1_TBL.t = 'one'; -- ok
SELECT * FROM (J1_TBL JOIN J2_TBL USING (i)) AS x WHERE J1_TBL.t = 'one'; -- error
SELECT * FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE x.i = 1; -- ok
SELECT * FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE x.t = 'one'; -- error
SELECT * FROM (J1_TBL JOIN J2_TBL USING (i) AS x) AS xx WHERE x.i = 1; -- error (XXX could use better hint)
SELECT * FROM J1_TBL a1 JOIN J2_TBL a2 USING (i) AS a1; -- error
SELECT x.* FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE J1_TBL.t = 'one';
SELECT ROW(x.*) FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE J1_TBL.t = 'one';
SELECT row_to_json(x.*) FROM J1_TBL JOIN J2_TBL USING (i) AS x WHERE J1_TBL.t = 'one';
--
-- NATURAL JOIN
-- Inner equi-join on all columns with the same name
--
SELECT *
FROM J1_TBL NATURAL JOIN J2_TBL;
SELECT *
FROM J1_TBL t1 (a, b, c) NATURAL JOIN J2_TBL t2 (a, d);
SELECT *
FROM J1_TBL t1 (a, b, c) NATURAL JOIN J2_TBL t2 (d, a);
-- mismatch number of columns
-- currently, Postgres will fill in with underlying names
SELECT *
FROM J1_TBL t1 (a, b) NATURAL JOIN J2_TBL t2 (a);
--
-- Inner joins (equi-joins)
--
SELECT *
FROM J1_TBL JOIN J2_TBL ON (J1_TBL.i = J2_TBL.i);
SELECT *
FROM J1_TBL JOIN J2_TBL ON (J1_TBL.i = J2_TBL.k);
--
-- Non-equi-joins
--
SELECT *
FROM J1_TBL JOIN J2_TBL ON (J1_TBL.i <= J2_TBL.k);
--
-- Outer joins
-- Note that OUTER is a noise word
--
SELECT *
FROM J1_TBL LEFT OUTER JOIN J2_TBL USING (i)
ORDER BY i, k, t;
SELECT *
FROM J1_TBL LEFT JOIN J2_TBL USING (i)
ORDER BY i, k, t;
SELECT *
FROM J1_TBL RIGHT OUTER JOIN J2_TBL USING (i);
SELECT *
FROM J1_TBL RIGHT JOIN J2_TBL USING (i);
SELECT *
FROM J1_TBL FULL OUTER JOIN J2_TBL USING (i)
ORDER BY i, k, t;
SELECT *
FROM J1_TBL FULL JOIN J2_TBL USING (i)
ORDER BY i, k, t;
SELECT *
FROM J1_TBL LEFT JOIN J2_TBL USING (i) WHERE (k = 1);
SELECT *
FROM J1_TBL LEFT JOIN J2_TBL USING (i) WHERE (i = 1);
--
-- semijoin selectivity for <>
--
explain (costs off)
select * from int4_tbl i4, tenk1 a
where exists(select * from tenk1 b
where a.twothousand = b.twothousand and a.fivethous <> b.fivethous)
and i4.f1 = a.tenthous;
--
-- More complicated constructs
--
--
-- Multiway full join
--
CREATE TABLE t1 (name TEXT, n INTEGER);
CREATE TABLE t2 (name TEXT, n INTEGER);
CREATE TABLE t3 (name TEXT, n INTEGER);
INSERT INTO t1 VALUES ( 'bb', 11 );
INSERT INTO t2 VALUES ( 'bb', 12 );
INSERT INTO t2 VALUES ( 'cc', 22 );
INSERT INTO t2 VALUES ( 'ee', 42 );
INSERT INTO t3 VALUES ( 'bb', 13 );
INSERT INTO t3 VALUES ( 'cc', 23 );
INSERT INTO t3 VALUES ( 'dd', 33 );
SELECT * FROM t1 FULL JOIN t2 USING (name) FULL JOIN t3 USING (name);
--
-- Test interactions of join syntax and subqueries
--
-- Basic cases (we expect planner to pull up the subquery here)
SELECT * FROM
(SELECT * FROM t2) as s2
INNER JOIN
(SELECT * FROM t3) s3
USING (name);
SELECT * FROM
(SELECT * FROM t2) as s2
LEFT JOIN
(SELECT * FROM t3) s3
USING (name);
SELECT * FROM
(SELECT * FROM t2) as s2
FULL JOIN
(SELECT * FROM t3) s3
USING (name);
-- Cases with non-nullable expressions in subquery results;
-- make sure these go to null as expected
SELECT * FROM
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL INNER JOIN
(SELECT name, n as s3_n, 3 as s3_2 FROM t3) s3;
SELECT * FROM
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL LEFT JOIN
(SELECT name, n as s3_n, 3 as s3_2 FROM t3) s3;
SELECT * FROM
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL FULL JOIN
(SELECT name, n as s3_n, 3 as s3_2 FROM t3) s3;
SELECT * FROM
(SELECT name, n as s1_n, 1 as s1_1 FROM t1) as s1
NATURAL INNER JOIN
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL INNER JOIN
(SELECT name, n as s3_n, 3 as s3_2 FROM t3) s3;
SELECT * FROM
(SELECT name, n as s1_n, 1 as s1_1 FROM t1) as s1
NATURAL FULL JOIN
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL FULL JOIN
(SELECT name, n as s3_n, 3 as s3_2 FROM t3) s3;
SELECT * FROM
(SELECT name, n as s1_n FROM t1) as s1
NATURAL FULL JOIN
(SELECT * FROM
(SELECT name, n as s2_n FROM t2) as s2
NATURAL FULL JOIN
(SELECT name, n as s3_n FROM t3) as s3
) ss2;
SELECT * FROM
(SELECT name, n as s1_n FROM t1) as s1
NATURAL FULL JOIN
(SELECT * FROM
(SELECT name, n as s2_n, 2 as s2_2 FROM t2) as s2
NATURAL FULL JOIN
(SELECT name, n as s3_n FROM t3) as s3
) ss2;
-- Constants as join keys can also be problematic
SELECT * FROM
(SELECT name, n as s1_n FROM t1) as s1
FULL JOIN
(SELECT name, 2 as s2_n FROM t2) as s2
ON (s1_n = s2_n);
-- Test for propagation of nullability constraints into sub-joins
create temp table x (x1 int, x2 int);
insert into x values (1,11);
insert into x values (2,22);
insert into x values (3,null);
insert into x values (4,44);
insert into x values (5,null);
create temp table y (y1 int, y2 int);
insert into y values (1,111);
insert into y values (2,222);
insert into y values (3,333);
insert into y values (4,null);
select * from x;
select * from y;
select * from x left join y on (x1 = y1 and x2 is not null);
select * from x left join y on (x1 = y1 and y2 is not null);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1 and x2 is not null);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1 and y2 is not null);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1 and xx2 is not null);
-- these should NOT give the same answers as above
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1) where (x2 is not null);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1) where (y2 is not null);
select * from (x left join y on (x1 = y1)) left join x xx(xx1,xx2)
on (x1 = xx1) where (xx2 is not null);
--
-- regression test: check for bug with propagation of implied equality
-- to outside an IN
--
select count(*) from tenk1 a where unique1 in
(select unique1 from tenk1 b join tenk1 c using (unique1)
where b.unique2 = 42);
--
-- regression test: check for failure to generate a plan with multiple
-- degenerate IN clauses
--
select count(*) from tenk1 x where
x.unique1 in (select a.f1 from int4_tbl a,float8_tbl b where a.f1=b.f1) and
x.unique1 = 0 and
x.unique1 in (select aa.f1 from int4_tbl aa,float8_tbl bb where aa.f1=bb.f1);
-- try that with GEQO too
begin;
set geqo = on;
set geqo_threshold = 2;
select count(*) from tenk1 x where
x.unique1 in (select a.f1 from int4_tbl a,float8_tbl b where a.f1=b.f1) and
x.unique1 = 0 and
x.unique1 in (select aa.f1 from int4_tbl aa,float8_tbl bb where aa.f1=bb.f1);
rollback;
--
-- regression test: be sure we cope with proven-dummy append rels
--
explain (costs off)
select aa, bb, unique1, unique1
from tenk1 right join b_star on aa = unique1
where bb < bb and bb is null;
select aa, bb, unique1, unique1
from tenk1 right join b_star on aa = unique1
where bb < bb and bb is null;
--
-- regression test: check handling of empty-FROM subquery underneath outer join
--
explain (costs off)
select * from int8_tbl i1 left join (int8_tbl i2 join
(select 123 as x) ss on i2.q1 = x) on i1.q2 = i2.q2
order by 1, 2;
select * from int8_tbl i1 left join (int8_tbl i2 join
(select 123 as x) ss on i2.q1 = x) on i1.q2 = i2.q2
order by 1, 2;
--
-- regression test: check a case where join_clause_is_movable_into()
-- used to give an imprecise result, causing an assertion failure
--
select count(*)
from
(select t3.tenthous as x1, coalesce(t1.stringu1, t2.stringu1) as x2
from tenk1 t1
left join tenk1 t2 on t1.unique1 = t2.unique1
join tenk1 t3 on t1.unique2 = t3.unique2) ss,
tenk1 t4,
tenk1 t5
where t4.thousand = t5.unique1 and ss.x1 = t4.tenthous and ss.x2 = t5.stringu1;
--
-- regression test: check a case where we formerly missed including an EC
-- enforcement clause because it was expected to be handled at scan level
--
explain (costs off)
select a.f1, b.f1, t.thousand, t.tenthous from
tenk1 t,
(select sum(f1)+1 as f1 from int4_tbl i4a) a,
(select sum(f1) as f1 from int4_tbl i4b) b
where b.f1 = t.thousand and a.f1 = b.f1 and (a.f1+b.f1+999) = t.tenthous;
select a.f1, b.f1, t.thousand, t.tenthous from
tenk1 t,
(select sum(f1)+1 as f1 from int4_tbl i4a) a,
(select sum(f1) as f1 from int4_tbl i4b) b
where b.f1 = t.thousand and a.f1 = b.f1 and (a.f1+b.f1+999) = t.tenthous;
--
-- check a case where we formerly got confused by conflicting sort orders
-- in redundant merge join path keys
--
explain (costs off)
select * from
j1_tbl full join
(select * from j2_tbl order by j2_tbl.i desc, j2_tbl.k asc) j2_tbl
on j1_tbl.i = j2_tbl.i and j1_tbl.i = j2_tbl.k;
select * from
j1_tbl full join
(select * from j2_tbl order by j2_tbl.i desc, j2_tbl.k asc) j2_tbl
on j1_tbl.i = j2_tbl.i and j1_tbl.i = j2_tbl.k;
--
-- a different check for handling of redundant sort keys in merge joins
--
explain (costs off)
select count(*) from
(select * from tenk1 x order by x.thousand, x.twothousand, x.fivethous) x
left join
(select * from tenk1 y order by y.unique2) y
on x.thousand = y.unique2 and x.twothousand = y.hundred and x.fivethous = y.unique2;
select count(*) from
(select * from tenk1 x order by x.thousand, x.twothousand, x.fivethous) x
left join
(select * from tenk1 y order by y.unique2) y
on x.thousand = y.unique2 and x.twothousand = y.hundred and x.fivethous = y.unique2;
set enable_hashjoin = 0;
set enable_nestloop = 0;
set enable_hashagg = 0;
--
-- Check that we use the pathkeys from a prefix of the group by / order by
-- clause for the join pathkeys when that prefix covers all join quals. We
-- expect this to lead to an incremental sort for the group by / order by.
--
explain (costs off)
select x.thousand, x.twothousand, count(*)
from tenk1 x inner join tenk1 y on x.thousand = y.thousand
group by x.thousand, x.twothousand
order by x.thousand desc, x.twothousand;
reset enable_hashagg;
reset enable_nestloop;
reset enable_hashjoin;
--
-- Clean up
--
DROP TABLE t1;
DROP TABLE t2;
DROP TABLE t3;
DROP TABLE J1_TBL;
DROP TABLE J2_TBL;
-- Both DELETE and UPDATE allow the specification of additional tables
-- to "join" against to determine which rows should be modified.
CREATE TEMP TABLE t1 (a int, b int);
CREATE TEMP TABLE t2 (a int, b int);
CREATE TEMP TABLE t3 (x int, y int);
INSERT INTO t1 VALUES (5, 10);
INSERT INTO t1 VALUES (15, 20);
INSERT INTO t1 VALUES (100, 100);
INSERT INTO t1 VALUES (200, 1000);
INSERT INTO t2 VALUES (200, 2000);
INSERT INTO t3 VALUES (5, 20);
INSERT INTO t3 VALUES (6, 7);
INSERT INTO t3 VALUES (7, 8);
INSERT INTO t3 VALUES (500, 100);
DELETE FROM t3 USING t1 table1 WHERE t3.x = table1.a;
SELECT * FROM t3;
DELETE FROM t3 USING t1 JOIN t2 USING (a) WHERE t3.x > t1.a;
SELECT * FROM t3;
DELETE FROM t3 USING t3 t3_other WHERE t3.x = t3_other.x AND t3.y = t3_other.y;
SELECT * FROM t3;
-- Test join against inheritance tree
create temp table t2a () inherits (t2);
insert into t2a values (200, 2001);
select * from t1 left join t2 on (t1.a = t2.a);
-- Test matching of column name with wrong alias
select t1.x from t1 join t3 on (t1.a = t3.x);
-- Test matching of locking clause with wrong alias
select t1.*, t2.*, unnamed_join.* from
t1 join t2 on (t1.a = t2.a), t3 as unnamed_join
for update of unnamed_join;
select foo.*, unnamed_join.* from
t1 join t2 using (a) as foo, t3 as unnamed_join
for update of unnamed_join;
select foo.*, unnamed_join.* from
t1 join t2 using (a) as foo, t3 as unnamed_join
for update of foo;
select bar.*, unnamed_join.* from
(t1 join t2 using (a) as foo) as bar, t3 as unnamed_join
for update of foo;
select bar.*, unnamed_join.* from
(t1 join t2 using (a) as foo) as bar, t3 as unnamed_join
for update of bar;
--
-- regression test for 8.1 merge right join bug
--
CREATE TEMP TABLE tt1 ( tt1_id int4, joincol int4 );
INSERT INTO tt1 VALUES (1, 11);
INSERT INTO tt1 VALUES (2, NULL);
CREATE TEMP TABLE tt2 ( tt2_id int4, joincol int4 );
INSERT INTO tt2 VALUES (21, 11);
INSERT INTO tt2 VALUES (22, 11);
set enable_hashjoin to off;
set enable_nestloop to off;
-- these should give the same results
select tt1.*, tt2.* from tt1 left join tt2 on tt1.joincol = tt2.joincol;
select tt1.*, tt2.* from tt2 right join tt1 on tt1.joincol = tt2.joincol;
reset enable_hashjoin;
reset enable_nestloop;
--
-- regression test for bug #13908 (hash join with skew tuples & nbatch increase)
--
set work_mem to '64kB';
set enable_mergejoin to off;
set enable_memoize to off;
explain (costs off)
select count(*) from tenk1 a, tenk1 b
where a.hundred = b.thousand and (b.fivethous % 10) < 10;
select count(*) from tenk1 a, tenk1 b
where a.hundred = b.thousand and (b.fivethous % 10) < 10;
reset work_mem;
reset enable_mergejoin;
reset enable_memoize;
--
-- regression test for 8.2 bug with improper re-ordering of left joins
--
create temp table tt3(f1 int, f2 text);
insert into tt3 select x, repeat('xyzzy', 100) from generate_series(1,10000) x;
analyze tt3;
create temp table tt4(f1 int);
insert into tt4 values (0),(1),(9999);
analyze tt4;
set enable_nestloop to off;
EXPLAIN (COSTS OFF)
SELECT a.f1
FROM tt4 a
LEFT JOIN (
SELECT b.f1
FROM tt3 b LEFT JOIN tt3 c ON (b.f1 = c.f1)
WHERE COALESCE(c.f1, 0) = 0
) AS d ON (a.f1 = d.f1)
WHERE COALESCE(d.f1, 0) = 0
ORDER BY 1;
SELECT a.f1
FROM tt4 a
LEFT JOIN (
SELECT b.f1
FROM tt3 b LEFT JOIN tt3 c ON (b.f1 = c.f1)
WHERE COALESCE(c.f1, 0) = 0
) AS d ON (a.f1 = d.f1)
WHERE COALESCE(d.f1, 0) = 0
ORDER BY 1;
reset enable_nestloop;
--
-- basic semijoin and antijoin recognition tests
--
explain (costs off)
select a.* from tenk1 a
where unique1 in (select unique2 from tenk1 b);
-- sadly, this is not an antijoin
explain (costs off)
select a.* from tenk1 a
where unique1 not in (select unique2 from tenk1 b);
explain (costs off)
select a.* from tenk1 a
where exists (select 1 from tenk1 b where a.unique1 = b.unique2);
explain (costs off)
select a.* from tenk1 a
where not exists (select 1 from tenk1 b where a.unique1 = b.unique2);
explain (costs off)
select a.* from tenk1 a left join tenk1 b on a.unique1 = b.unique2
where b.unique2 is null;
--
-- regression test for proper handling of outer joins within antijoins
--
create temp table tt4x(c1 int, c2 int, c3 int);
explain (costs off)
select * from tt4x t1
where not exists (
select 1 from tt4x t2
left join tt4x t3 on t2.c3 = t3.c1
left join ( select t5.c1 as c1
from tt4x t4 left join tt4x t5 on t4.c2 = t5.c1
) a1 on t3.c2 = a1.c1
where t1.c1 = t2.c2
);
--
-- regression test for problems of the sort depicted in bug #3494
--
create temp table tt5(f1 int, f2 int);
create temp table tt6(f1 int, f2 int);
insert into tt5 values(1, 10);
insert into tt5 values(1, 11);
insert into tt6 values(1, 9);
insert into tt6 values(1, 2);
insert into tt6 values(2, 9);
select * from tt5,tt6 where tt5.f1 = tt6.f1 and tt5.f1 = tt5.f2 - tt6.f2;
--
-- regression test for problems of the sort depicted in bug #3588
--
create temp table xx (pkxx int);
create temp table yy (pkyy int, pkxx int);
insert into xx values (1);
insert into xx values (2);
insert into xx values (3);
insert into yy values (101, 1);
insert into yy values (201, 2);
insert into yy values (301, NULL);
select yy.pkyy as yy_pkyy, yy.pkxx as yy_pkxx, yya.pkyy as yya_pkyy,
xxa.pkxx as xxa_pkxx, xxb.pkxx as xxb_pkxx
from yy
left join (SELECT * FROM yy where pkyy = 101) as yya ON yy.pkyy = yya.pkyy
left join xx xxa on yya.pkxx = xxa.pkxx
left join xx xxb on coalesce (xxa.pkxx, 1) = xxb.pkxx;
--
-- regression test for improper pushing of constants across outer-join clauses
-- (as seen in early 8.2.x releases)
--
create temp table zt1 (f1 int primary key);
create temp table zt2 (f2 int primary key);
create temp table zt3 (f3 int primary key);
insert into zt1 values(53);
insert into zt2 values(53);
select * from
zt2 left join zt3 on (f2 = f3)
left join zt1 on (f3 = f1)
where f2 = 53;
create temp view zv1 as select *,'dummy'::text AS junk from zt1;
select * from
zt2 left join zt3 on (f2 = f3)
left join zv1 on (f3 = f1)
where f2 = 53;
--
-- regression test for improper extraction of OR indexqual conditions
-- (as seen in early 8.3.x releases)
--
select a.unique2, a.ten, b.tenthous, b.unique2, b.hundred
from tenk1 a left join tenk1 b on a.unique2 = b.tenthous
where a.unique1 = 42 and
((b.unique2 is null and a.ten = 2) or b.hundred = 3);
--
-- test proper positioning of one-time quals in EXISTS (8.4devel bug)
--
prepare foo(bool) as
select count(*) from tenk1 a left join tenk1 b
on (a.unique2 = b.unique1 and exists
(select 1 from tenk1 c where c.thousand = b.unique2 and $1));
execute foo(true);
execute foo(false);
--
-- test for sane behavior with noncanonical merge clauses, per bug #4926
--
begin;
set enable_mergejoin = 1;
set enable_hashjoin = 0;
set enable_nestloop = 0;
create temp table a (i integer);
create temp table b (x integer, y integer);
select * from a left join b on i = x and i = y and x = i;
rollback;
--
-- test handling of merge clauses using record_ops
--
begin;
create type mycomptype as (id int, v bigint);
create temp table tidv (idv mycomptype);
create index on tidv (idv);
explain (costs off)
select a.idv, b.idv from tidv a, tidv b where a.idv = b.idv;
set enable_mergejoin = 0;
set enable_hashjoin = 0;
explain (costs off)
select a.idv, b.idv from tidv a, tidv b where a.idv = b.idv;
rollback;
--
-- test NULL behavior of whole-row Vars, per bug #5025
--
select t1.q2, count(t2.*)
from int8_tbl t1 left join int8_tbl t2 on (t1.q2 = t2.q1)
group by t1.q2 order by 1;
select t1.q2, count(t2.*)
from int8_tbl t1 left join (select * from int8_tbl) t2 on (t1.q2 = t2.q1)
group by t1.q2 order by 1;
select t1.q2, count(t2.*)
from int8_tbl t1 left join (select * from int8_tbl offset 0) t2 on (t1.q2 = t2.q1)
group by t1.q2 order by 1;
select t1.q2, count(t2.*)
from int8_tbl t1 left join
(select q1, case when q2=1 then 1 else q2 end as q2 from int8_tbl) t2
on (t1.q2 = t2.q1)
group by t1.q2 order by 1;
--
-- test incorrect failure to NULL pulled-up subexpressions
--
begin;
create temp table a (
code char not null,
constraint a_pk primary key (code)
);
create temp table b (
a char not null,
num integer not null,
constraint b_pk primary key (a, num)
);
create temp table c (
name char not null,
a char,
constraint c_pk primary key (name)
);
insert into a (code) values ('p');
insert into a (code) values ('q');
insert into b (a, num) values ('p', 1);
insert into b (a, num) values ('p', 2);
insert into c (name, a) values ('A', 'p');
insert into c (name, a) values ('B', 'q');
insert into c (name, a) values ('C', null);
select c.name, ss.code, ss.b_cnt, ss.const
from c left join
(select a.code, coalesce(b_grp.cnt, 0) as b_cnt, -1 as const
from a left join
(select count(1) as cnt, b.a from b group by b.a) as b_grp
on a.code = b_grp.a
) as ss
on (c.a = ss.code)
order by c.name;
rollback;
--
-- test incorrect handling of placeholders that only appear in targetlists,
-- per bug #6154
--
SELECT * FROM
( SELECT 1 as key1 ) sub1
LEFT JOIN
( SELECT sub3.key3, sub4.value2, COALESCE(sub4.value2, 66) as value3 FROM
( SELECT 1 as key3 ) sub3
LEFT JOIN
( SELECT sub5.key5, COALESCE(sub6.value1, 1) as value2 FROM
( SELECT 1 as key5 ) sub5
LEFT JOIN
( SELECT 2 as key6, 42 as value1 ) sub6
ON sub5.key5 = sub6.key6
) sub4
ON sub4.key5 = sub3.key3
) sub2
ON sub1.key1 = sub2.key3;
-- test the path using join aliases, too
SELECT * FROM
( SELECT 1 as key1 ) sub1
LEFT JOIN
( SELECT sub3.key3, value2, COALESCE(value2, 66) as value3 FROM
( SELECT 1 as key3 ) sub3
LEFT JOIN
( SELECT sub5.key5, COALESCE(sub6.value1, 1) as value2 FROM
( SELECT 1 as key5 ) sub5
LEFT JOIN
( SELECT 2 as key6, 42 as value1 ) sub6
ON sub5.key5 = sub6.key6
) sub4
ON sub4.key5 = sub3.key3
) sub2
ON sub1.key1 = sub2.key3;
--
-- test case where a PlaceHolderVar is used as a nestloop parameter
--
EXPLAIN (COSTS OFF)
SELECT qq, unique1
FROM
( SELECT COALESCE(q1, 0) AS qq FROM int8_tbl a ) AS ss1
FULL OUTER JOIN
( SELECT COALESCE(q2, -1) AS qq FROM int8_tbl b ) AS ss2
USING (qq)
INNER JOIN tenk1 c ON qq = unique2;
SELECT qq, unique1
FROM
( SELECT COALESCE(q1, 0) AS qq FROM int8_tbl a ) AS ss1
FULL OUTER JOIN
( SELECT COALESCE(q2, -1) AS qq FROM int8_tbl b ) AS ss2
USING (qq)
INNER JOIN tenk1 c ON qq = unique2;
--
-- nested nestloops can require nested PlaceHolderVars
--
create temp table nt1 (
id int primary key,
a1 boolean,
a2 boolean
);
create temp table nt2 (
id int primary key,
nt1_id int,
b1 boolean,
b2 boolean,
foreign key (nt1_id) references nt1(id)
);
create temp table nt3 (
id int primary key,
nt2_id int,
c1 boolean,
foreign key (nt2_id) references nt2(id)
);
insert into nt1 values (1,true,true);
insert into nt1 values (2,true,false);
insert into nt1 values (3,false,false);
insert into nt2 values (1,1,true,true);
insert into nt2 values (2,2,true,false);
insert into nt2 values (3,3,false,false);
insert into nt3 values (1,1,true);
insert into nt3 values (2,2,false);
insert into nt3 values (3,3,true);
explain (costs off)
select nt3.id
from nt3 as nt3
left join
(select nt2.*, (nt2.b1 and ss1.a3) AS b3
from nt2 as nt2
left join
(select nt1.*, (nt1.id is not null) as a3 from nt1) as ss1
on ss1.id = nt2.nt1_id
) as ss2
on ss2.id = nt3.nt2_id
where nt3.id = 1 and ss2.b3;
select nt3.id
from nt3 as nt3
left join
(select nt2.*, (nt2.b1 and ss1.a3) AS b3
from nt2 as nt2
left join
(select nt1.*, (nt1.id is not null) as a3 from nt1) as ss1
on ss1.id = nt2.nt1_id
) as ss2
on ss2.id = nt3.nt2_id
where nt3.id = 1 and ss2.b3;
--
-- test case where a PlaceHolderVar is propagated into a subquery
--
explain (costs off)
select * from
int8_tbl t1 left join
(select q1 as x, 42 as y from int8_tbl t2) ss
on t1.q2 = ss.x
where
1 = (select 1 from int8_tbl t3 where ss.y is not null limit 1)
order by 1,2;
select * from
int8_tbl t1 left join
(select q1 as x, 42 as y from int8_tbl t2) ss
on t1.q2 = ss.x
where
1 = (select 1 from int8_tbl t3 where ss.y is not null limit 1)
order by 1,2;