1486 XOR Operation in an Array

Given an integer n and an integer start.

Define an array nums where nums[i] = start + 2*i (0-indexed) and n == nums.length.

Return the bitwise XOR of all elements of nums.

 

Example 1:

Input: n = 5, start = 0
Output: 8
Explanation: Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8.
Where "^" corresponds to bitwise XOR operator.


public int xorOperation(int n, int start) {
        
       int[] nums = new int[n];
       for(int i=0;i<nums.length;i++){
           nums[i] = start +(2*i);
       }
        
       int xor = 0;
       //0^2^4^6^10 = 8
       for(int i=0;i<nums.length;i++){
           xor = xor^nums[i];
       }
       
       return xor;
        
    }