Equilibrium_index_of_an_array

/* Programmer     : Dhruv Patel
*  Problem Name   : Equilibrium index of an array
*  Used In        : geeksforgeeks
*  Used As        : Practice_Question
*  Problem        : 
*  Equilibrium index of an array is an index such that the sum of elements at lower indexes is equal to the 
*  sum of elements at higher indexes. For example, in an arrya A:
*  A[0] = -7, A[1] = 1, A[2] = 5, A[3] = 2, A[4] = -4, A[5] = 3, A[6]=0
*       3 is an equilibrium index, because:
*  A[0] + A[1] + A[2] = A[4] + A[5] + A[6]
*       6 is also an equilibrium index, because sum of zero elements is zero, i.e., A[0] + A[1] + A[2] + A[3] + A[4] + A[5]=0
*       7 is not an equilibrium index, because it is not a valid index of array A.
*
*  Thoughts     => 
*  The following code uses two for loops. One goes in forward direction and nested on goes into backward direction
*  which compare the sum with the outside loop if match found than prints the value of equilibrim index.
*/
class Equilibrium_index_of_an_array {
    public static void main(String args[]){
        int a [] = { -7, 1, 5, 2, -4, 3, 0};
        int sum = 0;
        int c_sum = 0;
        for(int i = 0 ; i < a.length-1 ; i++) {
            sum+=a[i];
            for(int j = i+1 ; j < a.length ; j++) {
                c_sum+=a[j];
                if(sum==c_sum){
                    System.out.println(i+1);
                }
            }
            c_sum=0;
        }
    }
}