特点:通过全局规划,将大问题分割成小问题来取最优解 案例:最少硬币找零 美国有以下面额(硬币):d1=1, d2=5, d3=10, d4=25 如果要找36美分的零钱,我们可以用1个25美分、1个10美分和1个便士( 1美分)
class MinCoinChange {
constructor(coins) {
this.coins = coins
this.cache = {}
}
makeChange(amount) {
if (!amount) return []
if (this.cache[amount]) return this.cache[amount]
let min = [], newMin, newAmount
this.coins.forEach(coin => {
newAmount = amount - coin
if (newAmount >= 0) {
newMin = this.makeChange(newAmount)
}
if (newAmount >= 0 &&
(newMin.length < min.length - 1 || !min.length) &&
(newMin.length || !newAmount)) {
min = [coin].concat(newMin)
}
})
return (this.cache[amount] = min)
}
}
const rninCoinChange = new MinCoinChange([1, 5, 10, 25])
console.log(rninCoinChange.makeChange(36))
// [1, 10, 25]
const minCoinChange2 = new MinCoinChange([1, 3, 4])
console.log(minCoinChange2.makeChange(6))
// [3, 3]
特点:通过最优解来解决问题
function MinCoinChange(coins) {
var coins = coins;
var cache = {};
this.makeChange = function(amount) {
var change = [],
total = 0;
for (var i = coins.length; i >= 0; i--) {
var coin = coins[i];
while (total + coin <= amount) {
change.push(coin);
total += coin;
}
}
return change;
};
}
var minCoinChange = new MinCoinChange([1, 5, 10, 25]);
console.log(minCoinChange.makeChange(36));
console.log(minCoinChange.makeChange(34));
console.log(minCoinChange.makeChange(6));