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Melhor detalhamento em um dos passos da questão 2 da lista 6, além de…
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… pequena correção na lista 5.
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pdroalves committed Jun 2, 2013
1 parent b80acd3 commit dc57241
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2 changes: 1 addition & 1 deletion lista5.tex
Expand Up @@ -59,7 +59,7 @@
\input{cover.tex}
\newpage
\setcounter{page}{1}
Equa\c{c}\~{o}es eventualmente útil:
Equa\c{c}\~{o}es eventualmente úteis:
\begin{align}
& f(x) = \sum_{n = 0}^\infty \frac{f^{(n)}(a)}{n!} (x - a)^n \tag{ST} \label{eq:ser_taylor} \\
& \Gamma(z) = \int_0^\infty e^{-t} t^{z - 1} \,\mathrm{d}t \tag{GE} \label{eq:gamma_euler} \\
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7 changes: 5 additions & 2 deletions lista6.tex
Expand Up @@ -179,9 +179,12 @@
&= i \left( \frac{\exp(i \theta) + \exp(-i \theta)}{2} \right) \\
&= i \cos \theta.
\end{align*}
Logo, por \eqref{eq:bessel_pri_esp_geratriz} para $t = i \exp(i \theta)$ temos
Logo, através da função geratriz \eqref{eq:bessel_pri_esp_geratriz}, para $t = i \exp(i \theta)$ temos que
\begin{align*}
\exp(i x \cos \theta) &= \sum_{k = -\infty}^{+\infty} (i \exp(i \theta))^k J_k(x) \\
\exp(i x \cos \theta) &= \exp(x \left(i \cos \theta \right))\\
&= \exp\left(x \frac{\left(t-t^{-1}\right)}{2}\right) \\
&= \sum_{k = -\infty}^{+\infty} t^k J_k(x) \\
&= \sum_{k = -\infty}^{+\infty} (i \exp(i \theta))^k J_k(x) \\
&= \sum_{k = -\infty}^{+\infty} i^k \exp(i k \theta) J_k(x).
\end{align*}
\end{solution}
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