Removed redundant validation.

kodecocodes · Dec 25, 2016 · 960bca1 · 960bca1
1 parent cf45ebd
commit 960bca1
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diff --git a/Boyer-Moore/BoyerMoore.playground/Contents.swift b/Boyer-Moore/BoyerMoore.playground/Contents.swift
@@ -9,9 +9,6 @@
 */
 extension String {
     func index(of pattern: String, usingHorspoolImprovement: Bool = false) -> Index? {
-        // There are no possible match in an empty string
-        guard !isEmpty else { return nil }
-
         // Cache the length of the search pattern because we're going to
         // use it a few times and it's expensive to calculate.
         let patternLength = pattern.characters.count

diff --git a/Boyer-Moore/BoyerMoore.swift b/Boyer-Moore/BoyerMoore.swift
@@ -7,9 +7,6 @@
 */
 extension String {
     func index(of pattern: String, usingHorspoolImprovement: Bool = false) -> Index? {
-        // There are no possible match in an empty string
-        guard !isEmpty else { return nil }
-
         // Cache the length of the search pattern because we're going to
         // use it a few times and it's expensive to calculate.
         let patternLength = pattern.characters.count

diff --git a/Boyer-Moore/README.markdown b/Boyer-Moore/README.markdown
@@ -33,9 +33,6 @@ Here's how you could write it in Swift:
 ```swift
 extension String {
     func index(of pattern: String) -> Index? {
-        // There are no possible match in an empty string
-        guard !isEmpty else { return nil }
-
         // Cache the length of the search pattern because we're going to
         // use it a few times and it's expensive to calculate.
         let patternLength = pattern.characters.count
@@ -160,9 +157,6 @@ Here's an implementation of the Boyer-Moore-Horspool algorithm:
 ```swift
 extension String {
     func index(of pattern: String) -> Index? {
-        // There are no possible match in an empty string
-        guard !isEmpty else { return nil }
-
         // Cache the length of the search pattern because we're going to
         // use it a few times and it's expensive to calculate.
         let patternLength = pattern.characters.count