Simplest way to print function called with the arguments that were passed

[vadi2]

What is the simplest way to print function called with the arguments that were passed? I'm debugging an interface implementation, so I don't have so much control over who is calling me methods; rather I am on the receiving end of them being called.

I can add IC() at the beginning of a function to see its name and arguments, but the argument values themselves aren't printed.

[renatoGarcia]

If I understand your question correctly, in a code like:

// ------------ Your code
void my_function(int a, float b)
{
    IC(a, b);
}

// ------------ External code calling your function
int foo = 7;
my_function(foo, 3.14)

You will print the arguments of my_function with IC(a, b). That will print something like:

ic| a: 7, b: 3.14

Unfortunately the variable names used at calling site (foo and 3.14) are not accessible inside of my_function.

[vadi2]

That does work, but it then doesn't say which function was called unlike IC() by itself. I see that there's a config toggle for prefixing the function called to all output - perhaps that is the best way?

[renatoGarcia]

Oh, sure. So you are right. You will need call

icecream::ic.include_context(true);

With that all calls to IC* macros all around the code will print the source name, line number, and function signature.

You gave me a new idea. Maybe a way to print the context along with the values would be nice. Let's say something at the lines of

IC(IC_CTX, foo, bar)
IC_CTX(foo, bar)

Food for thought.

[vadi2]

Yep, that would be perfect 👍

[vadi2]

Did this end up making it in?

[renatoGarcia]

Hi @vadi2. Not yet, but it is on my roadmap. I just need find some free time to put the work on.
I will go with the IC_CTX(...) option.