not working

[zoujunrong]

// "github.com/robfig/cron/v3"

func main() {
  c := cron.New()
  c.AddFunc("* * * * * *", func() {
    fmt.Println("working")
  })
  c.Start()
  
  select {}
}

use the latest version v3.0.1 and 3.0.0 is also not working, my useage was wrong?

[AdmiralDollBug]

It also happens on me. All of the jobs configured in format of cron expression does not work.
cron version: v3.0.1
go version: 1.15.2

[fujiawei-dev]

Me too...

[Alanthur]

The example was wrong. You should take 5 fields for AddFunc funtion.
correct:
c.AddFunc("30 3 * * *", func() { fmt.Println("working") })
wrong:
c.AddFunc("0 30 * * * *", func() { fmt.Println("working") })

[AdmiralDollBug]

I read the code again, and found that the cron.New function without parameter creates a "standardParser", which does not support the "Second" field

var standardParser = NewParser(
	Minute | Hour | Dom | Month | Dow | Descriptor,
)

...

func New(opts ...Option) *Cron {
	c := &Cron{
		entries:   nil,
		chain:     NewChain(),
		add:       make(chan *Entry),
		stop:      make(chan struct{}),
		snapshot:  make(chan chan []Entry),
		remove:    make(chan EntryID),
		running:   false,
		runningMu: sync.Mutex{},
		logger:    DefaultLogger,
		location:  time.Local,
		parser:    standardParser,
	}
	for _, opt := range opts {
		opt(c)
	}
	return c
}

To support "Second" field, create the cron object like this:

cron.New(cron.WithSeconds())

BTW，the doc on go.pkg.dev needs to be updated because it's misleading now...

[zoujunrong]

The example was wrong. You should take 5 fields for AddFunc funtion.
correct:
c.AddFunc("30 3 * * *", func() { fmt.Println("working") })
wrong:
c.AddFunc("0 30 * * * *", func() { fmt.Println("working") })

c.AddFunc("* * * * * *", func() { fmt.Println("working") })
also not working.

[danielMensah]

Has this issue been solve? having issues just running c.AddFunc("* * * * *", func() { fmt.Println("working") })

[grosenberry]

Has this issue been solve? having issues just running c.AddFunc("* * * * *", func() { fmt.Println("working") })

I was not able to get this line to work successfully, the only way I've found to get this to work is to use the above suggestion cron.New(cron.WithSeconds()) with the 6 field notation and it began working perfectly.

Hopefully this helps anyone landing on the page. I'm on v3.0.1.

[zoujunrong]

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