https://leetcode-cn.com/problems/two-sum/
难度:简单
/**
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = function(nums, target) {
var obj = {};
for(var i=0; i< nums.length;i++) {
const item = nums[i];
if(obj[item] >= 0) {
return [obj[item], i]
} else {
obj[target - item] = i;
}
}
};