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The expression gets transformed into !(!a || !(b || c)), which is correct.
However, applying it again on the first logical-or transforms the expression into (a && b || c) instead of the original expression.
A similar issue occurs when you start with a || (b && c) instead.
Starting from
The expression gets transformed into
!(!a || !(b || c))
, which is correct.However, applying it again on the first logical-or transforms the expression into
(a && b || c)
instead of the original expression.A similar issue occurs when you start with
a || (b && c)
instead.rust-analyzer version: rust-analyzer version: 0.3.1575-standalone (ff485b6 2023-07-02)
rustc version: rustc 1.70.0 (90c541806 2023-05-31)
relevant settings: Not Applicable
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