get Current File/Line of Lua Code

[codeaddicted]

Hi,

me again. Short question. Is there any way to get the currently executed filename and line of the lua code when inside of a lua executed c++ function directly over kaguya or do i need to use this->_internalLua.state() and debug library stuff?

best Regards
Christoph

[satoren]

kaguya doesn't have that feature
Use lua_getstack with lua_State.

[satoren]

Example in my debugger code stack_info class

Usage

   // get all stack info(0 is top)
    std::vector<stack_info> ret;
    ret.push_back(stack_info(state, 0));
    while (ret.back().is_available()) {
      ret.push_back(stack_info(state, ret.size()));
    }
    ret.pop_back();

    printf("top stack line: %d source: %s",ret[0].currentline(), ret[0].source());

[codeaddicted]

Hi,

thank you for the response. because i only need the current line and filename i solved it the following way:

int line;
std::string file;
lua_Debug ar;

lua_getstack(l.state(), 1, &ar);
lua_getinfo(l.state(), "Sl", &ar);

file = ar.source;
line = ar.currentline;

Best Regards
Christoph