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The website https://leleivre.com/rf_gammatoz.html takes Gamma in Mag and Ang in degree, that is, the following values: import skrf as rf
gamma_opt = (0.29614796004509125+0.3039039572306889j)
rf.complex_2_magnitude(gamma_opt) # --> 0.4243362221863005
rf.complex_2_degree(gamma_opt) # --> 45.740537854365876 using these values into the online calculator gives 69.75 + 51.70j Ohm for Z0=50 Ohm, which matches scikit-rf result. Note that you have another way of doing this calculation using the transmission lines functions of scikit-rf: import skrf as rf
rf.Gamma0_2_zl(Gamma=gamma_opt, z0=50) # --> array([69.75052436+51.70498367j]) |
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I have a python code to convert gamma to impedance:
which gives me the answer
z_s = (69.75052435645519+51.70498367058532j)
which is way off compared to online calculator at https://leleivre.com/rf_gammatoz.html
92+j0.3 ohm.
What am I doing wrong?
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