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Questions with regard to the bond with the next neighbor is part of a ring #11
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Toluene does not fit in this rule, since the C-C bond is not part of a ring, so it would indeed be cut to a benzene.
We always want to take the first 3 neighbors in the fragment (the default), so if you cut C-O-C into C, you artificially make one fragment smaller than usual. Cutting after 2 bonds is not a good idea I think. So, it will instead be cut after the final C. |
@selimsami Thank you for the explanation. I'm testing a molecule I would imagine that to test the central dihedral, the original molecule will be cut to (obviously the hydrogens will be added properly) This is the toluene to benzene transformation that I was talking about. |
Oh, I see the first three neighbours. Sorry for the Confusion. I wonder where did you get the first three neighbour definitions? It seems to me that two neighbours would be fine as well. I know obviously, that the more conservative the more accurate it is. |
Thank you. |
Chemical intuition and practical experience. You can of course change the default value with the frag_threshold keyword to whichever value you prefer.
This is not always true actually. Larger fragments tend to cause all sorts of problems with hysteresis and what not. So if you show that a threshold of 2 is sufficient to capture the chemical environment of the dihedral, then you are better off with 2. |
I have finished the ORCA module and is currently testing it.
In the paper, it is said that
The automated fragment generation works in the following way: When a flexible dihedral is identified, the first three neighbors of the central atoms of that dihedral are by default taken as part of the fragment. Then, the next atoms are removed and the fragment is capped with a hydrogen atom unless:
I wonder why (2)? It seems to me that it is ok to cap the toluene to benzene?
With regard to (3), I do agree that cutting C-O-C to C-O-H is bad, but cutting C-O-C to C seems ok to me?
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