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1693.daily-leads-and-partners.sql
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1693.daily-leads-and-partners.sql
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--
-- @lc app=leetcode id=1693 lang=mysql
--
-- [1693] Daily Leads and Partners
--
-- @lc code=start
/*
Input:
DailySales table:
+-----------+-----------+---------+------------+
| date_id | make_name | lead_id | partner_id |
+-----------+-----------+---------+------------+
| 2020-12-8 | toyota | 0 | 1 |
| 2020-12-8 | toyota | 1 | 0 |
| 2020-12-8 | toyota | 1 | 2 |
| 2020-12-7 | toyota | 0 | 2 |
| 2020-12-7 | toyota | 0 | 1 |
| 2020-12-8 | honda | 1 | 2 |
| 2020-12-8 | honda | 2 | 1 |
| 2020-12-7 | honda | 0 | 1 |
| 2020-12-7 | honda | 1 | 2 |
| 2020-12-7 | honda | 2 | 1 |
+-----------+-----------+---------+------------+
For each date_id and make_name,
find the number of distinct lead_id's
and distinct partner_id's.
Output:
+-----------+-----------+--------------+-----------------+
| date_id | make_name | unique_leads | unique_partners |
+-----------+-----------+--------------+-----------------+
| 2020-12-8 | toyota | 2 | 3 |
| 2020-12-7 | toyota | 1 | 2 |
| 2020-12-8 | honda | 2 | 2 |
| 2020-12-7 | honda | 3 | 2 |
+-----------+-----------+--------------+-----------------+
*/
select date_id, make_name,
count(distinct(lead_id)) as unique_leads,
count(distinct(partner_id)) as unique_partners
from DailySales
group by date_id, make_name
-- @lc code=end