/
BinaryTreeZigzagLevelOrderTraversal.cpp
51 lines (50 loc) · 1.22 KB
/
BinaryTreeZigzagLevelOrderTraversal.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
/*
*Binary Tree Zigzag Level Order Traversal
*Author: shuaijiang
*Email: zhaoshuaijiang8@gmail.com
*/
#include<iostream>
#include<stdlib.h>
using namespace std;
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
vector<vector<int>> result;
vector<TreeNode*> currLevel, nextLevel;
if(root==NULL)
return result;
currLevel.push_back(root);
for(int count=0;currLevel.size()>0;count++){
vector<int> vec;
for(int i=currLevel.size()-1;i>=0;i--){
TreeNode * node = currLevel[i];
vec.push_back(node->val);
if(count%2==0){
if(node->left)
nextLevel.push_back(node->left);
if(node->right)
nextLevel.push_back(node->right);
}
else{
if(node->right)
nextLevel.push_back(node->right);
if(node->left)
nextLevel.push_back(node->left);
}
}
result.push_back(vec);
currLevel = nextLevel;
nextLevel.clear();
}
return result;
}
};