My answers for the Project Euler code challenges on FreeCodeCamp.com
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If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below the provided parameter value number.
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function multiplesOf3and5(number) {
let result = 0;
for (let i = 0; i < number; i++) {
if (i % 3 === 0 || i % 5 === 0) {
result += i;
}
}
return result;
}
multiplesOf3and5(1000);
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Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be:
1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
Find the sum of all the multiples of 3 or 5 below the provided parameter value number.
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function fiboEvenSum(n) {
let n1 = 1;
let n2 = n1;
let evenSum = 0;
for (let i = 0; i < n; i++) {
let sum = n1 + n2;
if (sum > n) {
break;
} else if (sum % 2 === 0) {
evenSum += sum;
}
n1 = n2;
n2 = sum;
}
return evenSum;
}
fiboEvenSum(10);
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The prime factors of 13195 are 5, 7, 13 and 29.
What is the largest prime factor of the given number?
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function largestPrimeFactor(number) {
const primeFactors = [];
for (let i = 1; i <= number; i++) {
if (number % i === 0) {
let facStorage = [];
for (let j = 1; j <= i; j++) {
if (i % j === 0) {
facStorage.push(j);
}
}
if (facStorage.length <= 2) {
primeFactors.push(i);
}
}
}
return primeFactors[primeFactors.length - 1];
}
largestPrimeFactor(13195);
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A palindromic number reads the same both ways. The largest palindrome made from the product of two 2-digit numbers is 9009 = 91 × 99.
Find the largest palindrome made from the product of two n-digit numbers.
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const palindromeFinder = (numStr) => {
if (numStr.length <= 1) return true;
if (numStr[0] === numStr[numStr.length - 1]) {
return palindromeFinder(numStr.slice(1, numStr.length - 1));
} else return false;
};
const largestPalindromeProduct = (n) => {
let num = 10 ** n - 1;
let maxPal = 0;
for (let i = num; i > 0; i--) {
for (let j = i; j > 0; j--) {
let product = j * i;
if (palindromeFinder(product.toString())) {
if (product > maxPal) maxPal = product;
}
}
}
return maxPal;
};
largestPalindromeProduct(2);