print-the-elements-of-a-linked-list-in-reverse.py

"""
 Print elements of a linked list in reverse order as standard output
 head could be None as well for empty list
 Node is defined as
 
 class Node(object):
 
   def __init__(self, data=None, next_node=None):
       self.data = data
       self.next = next_node

 
"""

def ReversePrint(head):
    if head is None:
        return
    else:
        out = []
        node = head
        
        while node != None:
            out.append(node.data)
            node = node.next
            
        print("\n".join(map(str, out[::-1])))