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One of the reasons we can't return True from something like x > x - 1 is that this should only evaluate if x is real. But instead of leaving it unevaluated (as if to say nothing can be said) we could return x < oo or x > -oo. Basically, the same operator could be used with the appropriate oo on the rhs, e.g. x <= x + 1 -> x <= oo.
The text was updated successfully, but these errors were encountered:
One of the reasons we can't return True from something like
x > x - 1
is that this should only evaluate ifx
is real. But instead of leaving it unevaluated (as if to say nothing can be said) we could returnx < oo
orx > -oo
. Basically, the same operator could be used with the appropriateoo
on the rhs, e.g.x <= x + 1
->x <= oo
.The text was updated successfully, but these errors were encountered: