You signed in with another tab or window. Reload to refresh your session.You signed out in another tab or window. Reload to refresh your session.You switched accounts on another tab or window. Reload to refresh your session.Dismiss alert
The function Hecke.reduce_mod_powers(a::nf_elem, n::Int) has been advertised in oscar-system/Oscar.jl/pull/2748.
The interesting situation there is n == 2, and I get the following examples.
julia> K, z = cyclotomic_field(7); a = (z + z^6)^2;
julia> Hecke.reduce_mod_powers(a, 2) # the square is detected as such, fine
1^1
julia> Hecke.reduce_mod_powers(4*a, 2) # the given value is still a square, but the common coefficient 4 is not dealt with
4^1
julia> Hecke.reduce_mod_powers(z, 2) # this root of unity is not detected as the square of z^4
z_7^1
Am I perhaps asking the wrong questions?
(is_square says that the above values are squares.)
The text was updated successfully, but these errors were encountered:
Sorry, I forgot to replay to oscar-system/Oscar.jl#2748 (comment). The problem is that reduce_mod_powers does not guarantees what you want. It tries to reduce, but it does not, for example, factor anything.
@thofma O.k., then I will close this issue.
(The documentation of Hecke.reduce_mod_powers does not promise more than what the function does.
It could be improved: Write "integer", write a not \alpha, and the return value is a FacElem not a nf_elem.)
The function
Hecke.reduce_mod_powers(a::nf_elem, n::Int)
has been advertised in oscar-system/Oscar.jl/pull/2748.The interesting situation there is
n == 2
, and I get the following examples.Am I perhaps asking the wrong questions?
(
is_square
says that the above values are squares.)The text was updated successfully, but these errors were encountered: