What about default implementations for SequenceType? #1
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Notes regarding
<*>
: It doesn't seem possible to create a generic type constraint over a sequence ofA -> B
, so this version uses[A -> B]
as a workaround (which is no problem when combined with<^>
, which returns anArray
). i.e., Swift borks at this:I didn't think too hard about style, naming, etc., that's all up for grabs! Just keen to know if you're into this idea.