course |
course_year |
question_number |
tags |
title |
year |
Complex Methods |
IB |
13 |
|
Paper 4, Section II, A |
2010 |
A linear system is described by the differential equation
$$y^{\prime \prime \prime}(t)-y^{\prime \prime}(t)-2 y^{\prime}(t)+2 y(t)=f(t),$$
with initial conditions
$$y(0)=0, \quad y^{\prime}(0)=1, \quad y^{\prime \prime}(0)=1$$
The Laplace transform of $f(t)$ is defined as
$$\mathcal{L}[f(t)]=\tilde{f}(s)=\int_{0}^{\infty} e^{-s t} f(t) d t$$
You may assume the following Laplace transforms,
$$\begin{aligned}
\mathcal{L}[y(t)] &=\tilde{y}(s) \\
\mathcal{L}\left[y^{\prime}(t)\right] &=s \tilde{y}(s)-y(0) \\
\mathcal{L}\left[y^{\prime \prime}(t)\right] &=s^{2} \tilde{y}(s)-s y(0)-y^{\prime}(0) \\
\mathcal{L}\left[y^{\prime \prime \prime}(t)\right] &=s^{3} \tilde{y}(s)-s^{2} y(0)-s y^{\prime}(0)-y^{\prime \prime}(0)
\end{aligned}$$
(a) Use Laplace transforms to determine the response, $y_{1}(t)$, of the system to the signal
$$f(t)=-2$$
(b) Determine the response, $y_{2}(t)$, given that its Laplace transform is
$$\tilde{y}_{2}(s)=\frac{1}{s^{2}(s-1)^{2}} .$$
(c) Given that
$$y^{\prime \prime \prime}(t)-y^{\prime \prime}(t)-2 y^{\prime}(t)+2 y(t)=g(t)$$
leads to the response with Laplace transform
$$\tilde{y}(s)=\frac{1}{s^{2}(s-1)^{2}},$$
determine $g(t)$.