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8987 - Subsequence #20103

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fengjinlong opened this issue Nov 30, 2022 · 0 comments

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fengjinlong commented Nov 30, 2022

// your answers
type A1 = Subsequence<[1, 2]>; // [] | [1] | [2] | [1, 2]
type Subsequence<Arr> = Arr extends [infer f, ...infer r]
  ? Subsequence<r> | [f, ...Subsequence<r>]
  : [];

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