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// 你的答案 type NumberToString<T extends number> = `${T}` type StringToNumber<T extends string> = T extends `${infer F extends number}` ? F : never type StringToArray<T extends string> = T extends `${infer F}${infer Rest}` ? [F, ...StringToArray<Rest>] : [] type MinusNum = { '0': '9' '1': '0' '2': '1' '3': '2' '4': '3' '5': '4' '6': '5' '7': '6' '8': '7' '9': '8' } type AddNum = { '0': '1' '1': '2' '2': '3' '3': '4' '4': '5' '5': '6' '6': '7' '7': '8' '8': '9' '9': '0' } type PosAndNeg<T extends string[]> = T extends [infer F, ...any] ? F extends '-' ? ArrayAdd<T> : ArraySub<T> : never type ArraySub<T extends string[], U extends string[] = []> = T extends [...infer Rest extends string[], infer L] ? L extends keyof MinusNum ? L extends '0' ? ArraySub<Rest, [MinusNum[L], ...U]> : [...Rest, MinusNum[L], ...U] : never : never type ArrayAdd<T extends string[], U extends string[] = []> = T extends [...infer Rest extends string[], infer L] ? L extends keyof AddNum ? L extends '9' ? ArrayAdd<Rest, [AddNum[L], ...U]> : [...Rest, AddNum[L], ...U] : U[0] extends '0' ? [L, '1', ...U] : [L, ...U] : 1 type ArrayToString<T extends string[]> = T extends [infer F extends string, ...infer Rest extends string[]] ? `${F}${ArrayToString<Rest>}` : '' type Remove0<T extends string> = T extends `0${infer Rest}` ? Rest extends '' ? T : Remove0<Rest> : T type MinusOne<T extends number> = T extends 0 ? -1 : StringToNumber<Remove0<ArrayToString<PosAndNeg<StringToArray<NumberToString<T>>>>>>
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